tictactoe类二维数组有问题

Question

public class Board
{
    // instance variables - replace the example below with your own
    public int SIZE = 3;
    private char BLANK = 'N';
    private char [][] board;

    /**
     * Constructor for objects of class Board, intializes all elements to BLANK, 
     * creates board with SIZE elements
     */
  public Board()
    {
        // initialise instance variables
        board = new char[SIZE][SIZE];
        for(int i = 0; i < board.length; i++){
            for(int j = 0; j < board.length; j++){
                board[i][j] = BLANK;
        }
    }
   }
   /**
    * this method returns the board
    */
   public char [][] getBoard(){

       return board;
    }
    /**
     * prints the elements of the array board in a 3x3 grid
     */
   public void display(){
         for(int i = 0; i < board.length; i++){
            for(int j = 0; j < board.length; j++){
                System.out.print(board[i][j]);
        }
    }
   }
    /**
     * This method assigns X to the appropriate index in board
     */
   public void setX(int index){
       index = index - 1;
          for(int i = 0; i < board.length; i++){
            for(int j = 0; j < board.length; j++){

                if((BLANK <= index) && (index <= board[i][j])){
                    board[i][j] = 'X';
                }
        }
    }

    }
    /**
    * This method assigns O to the appropriate index in board
    */
   public void setO(int index){

       for(int i = 0; i < board.length; i++){
            for(int j = 0; j < board.length; j++){

                if((BLANK <= index) && (index <= board[i][j])){
                    board[i][j] = 'O';
                }
        }
    }
    }
   /**
    * This method returns true if the index is not occupied by an X or O
    */
    public boolean isAvailable(int index){
        boolean available = false;
        for(int i = 0; i < board.length; i++){
            for(int j = 0; j < board.length; j++){
                board[i][j] = BLANK;
               available = true;
        }
    }
        return available;
    }
}

Answer 1

首先，我想知道为什么你甚至需要一个二维数组。为什么不把板子表示为九元单阵呢？

除此之外，将1-9位置索引转换为适当的二维索引的方法是：

int i = (index - 1) / 3;
int j = (index - 1) % 3;

然后处理board[i][j]只处理这一对索引。您的setx和seto方法不应循环。