检查胜利者TIC TAC脚趾

Question

我想这一定是一个简单的修复，但我仍然熟悉编码，所以偶尔我会陷入一些愚蠢的事情（会赶上的，最终哈哈）

def player_char():

    marker = ''
    player1 = ''
    player2 = ''

    # Keep asking Player 1 to choose X or O, until entry is correct:
    while marker != ('x').lower() and marker != ('o').lower():
        marker = input("\n PLAYER 1 - CHOOSE X OR O : ")

    # Assign opposite marker to Player 2
        player1 = marker.upper()
        if player1 == 'X':
            player2 = 'O'
        else:
            player2 = 'X'

    print (f"\n P1 playing with: {player1}" + f"\n P2 playing with: {player2}")
    markers = [player1, player2]
    return markers

def check_victory(board, markers):

    player1_win = False
    player2_win = False
    draw = False

    # Check if players win the game in one of the lines, columns or diagonals available
    for n in range(len(markers)):
        if board[7] == board[8] == board[9] == markers[n]:
            if n == 0:
                player1_win = True
            else:
                player2_win = True
            break

（我已经实现了所有其他可能获胜的行和列。没有将它们粘贴在这里以使问题更短，但它们都遵循上面的逻辑）

当玩家放置标记时，我调用该函数，一旦满足一个获胜条件，我会打印消息：

if player1_win:
   print("\n >>> GAME FINISHED! PLAYER 1 WINS!")
if player2_win:
   print("\n >>> GAME FINISHED! PLAYER 2 WINS!")

但游戏不会中断（我猜会是，因为我在每个条件后都“Rest”）。我的IF里面会发生什么？就像我说的，猜测一定很简单，但现在卡住了。

moves = 1

while winner[0] or winner[1] or winner[2] != True:
        if moves % 2 == 1:
            display_board(game_board, free)
            print(game_board)
            p1 = (input("\n >>> ( P1 ) Enter number for your move: "))                
            board[position_p1] = markers[0]
            moves += 1
            check_victory(board, markers)

Answer 1

内部if条件中的break将从该if条件中中断。

相反，您可以在最后再设置一个条件，检查以下任何一个条件是否为真，然后跳出for循环。player1_win=True或player2_win=True或draw=True