如何为“android 10”设备获取唯一的设备id？

Question

现在与android 10更新的权限和安全性，我们不能访问用户的设备ID和IMEI号码，但我想要一些设备的唯一ID，以便我们可以跟踪用户。

要求是我们想要/限制一部手机的一次登录

Answer 1

由于序列号和IMEI号已被Android 10及以后版本弃用，因此我们可以找到具有READ_PRIVILEGED_PHONE_状态的唯一标识符的Android id。

更多信息请点击下面的链接。https://developer.android.com/training/articles/user-data-ids

Answer 2

Android引入了一个新的id来唯一地标识一个设备，称为Advertision_id。您可以从应用程序类onCreate方法中的以下代码实现中获取该id。

/** Retrieve the Android Advertising Id 
     * 
     * The device must be KitKat (4.4)+ 
     * This method must be invoked from a background thread.
     * 
     * */
    public static synchronized String getAdId (Context context) {

        if (android.os.Build.VERSION.SDK_INT < android.os.Build.VERSION_CODES.KITKAT) {
            return null;
        }

        AdvertisingIdClient.Info idInfo = null;
        try {
            idInfo = AdvertisingIdClient.getAdvertisingIdInfo(context);
        } catch (GooglePlayServicesNotAvailableException e) {
            e.printStackTrace();
        } catch (GooglePlayServicesRepairableException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        String advertId = null;
        try{
            advertId = idInfo.getId();
        }catch (NullPointerException e){
            e.printStackTrace();
        }

        return advertId;
    }

为了科特林

     fun getAdId() {
        //Background Task
        AsyncTask.execute {
            var adInfo: AdvertisingIdClient.Info? = null
            try {
                adInfo = AdvertisingIdClient.getAdvertisingIdInfo(applicationContext)

                if(adInfo!=null){
                    val id = adInfo!!.getId()
                    val isLAT = adInfo!!.isLimitAdTrackingEnabled()

                    PersistData.setStringData(applicationContext, AppConstant.advertId, id)

                    val advertId = PersistData.getStringData(applicationContext, AppConstant.advertId)

                }

            } catch (e: IOException) {
                // Unrecoverable error connecting to Google Play services (e.g.,
                // the old version of the service doesn't support getting AdvertisingId).

            } catch (e: GooglePlayServicesAvailabilityException) {
                // Encountered a recoverable error connecting to Google Play services.

            } catch (e: GooglePlayServicesNotAvailableException) {
                // Google Play services is not available entirely.
            }


        }
    }

Answer 3

Android 10限制开发者访问IMEI号码。

您可以通过获取软件ID来获得替代解决方案。您可以使用软件ID作为唯一的ID。请在下面找到我在应用程序中使用的代码。

public static String getDeviceId(Context context) {
    
     String deviceId;
    
        if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
            deviceId = Settings.Secure.getString(
                    context.getContentResolver(),
                    Settings.Secure.ANDROID_ID);
        } else {
            final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
            if (mTelephony.getDeviceId() != null) {
                deviceId = mTelephony.getDeviceId();
            } else {
                deviceId = Settings.Secure.getString(
                        context.getContentResolver(),
                        Settings.Secure.ANDROID_ID);
            }
        }
    
        return deviceId;
    }