BigInteger没有最大长度吗？如果它有，我如何找到BigInteger DataType的最大长度？

Question

当我尝试对BigInteger使用MAX_VALUE时，它给出>>ERROR>>找不到符号变量MAX_VALUE

public class ALL_datatype_length {
    public static void main(String [] args){

        byte a = Byte.MAX_VALUE;
        short b = Short.MAX_VALUE;
        int c = Integer.MAX_VALUE;
        long d = Long.MAX_VALUE;
        float e = Float.MAX_VALUE;
        double f = Double.MAX_VALUE;

        BigInteger g = BigInteger.MAX_VALUE;     //   >> Shows ERROR

        System.out.println(a + "\t\t\t\tMaximum value of byte");
        System.out.println(b + "\t\t\t\tMaximum value of short");
        System.out.println(c + "\t\t\tMaximum value of integer");
        System.out.println(d + "\t\tMaximum value of long");
        System.out.println(e + "\t\t\tMaximum value of float");
        System.out.println(f + "\t\tMaximum value of double");
    }
}

Answer 1

来自Javadoc：类BigInteger

BigInteger必须支持范围为-2^{Integer.max_value}（独占）到+2^{Integer.max_value}（独占）的值，并且可能支持该范围以外的值。当BigInteger构造函数或方法生成的值超出所支持的范围时，将引发一个AlithmeticException。可能素数值的范围是有限的，可能小于BigInteger的完全支持的正范围。范围必须至少为1到2^500000000。

执行说明：

// Same can be done for the negative value as well
BigInteger twoBigInteger = BigInteger.valueOf(2);
BigInteger intMaxBigInteger = BigInteger.valueOf(Integer.MAX_VALUE);
BigInteger bigInteger = twoBigInteger.pow(intMaxBigInteger.intValue());
System.out.println(bigInteger.intValue());

Exception in thread "main" java.lang.ArithmeticException: BigInteger would overflow supported range
    at java.math.BigInteger.reportOverflow(BigInteger.java:1084)
    at java.math.BigInteger.checkRange(BigInteger.java:1079)
    at java.math.BigInteger.<init>(BigInteger.java:1055)
    at java.math.BigInteger.shiftLeft(BigInteger.java:3174)
    at java.math.BigInteger.pow(BigInteger.java:2339)
    at MyClass.main(MyClass.java:7)