Jackson Json到POJO映射

Question

我和jackson一起绘制地图，我有点迷茫。我的Json具有以下结构

    {
  "d": {
    "__metadata": {
      "uri": "https://apisalesdemo8.successfactors.com:443/odata/v2/JobApplication(1463L)",
      "type": "SFOData.JobApplication"
    },
    "lastName": "K",
    "address": "123 Main Street",
    "cellPhone": "12345",
    "firstName": "Katrin",
    "city": "Anytown",
    "country": "United States",
    "custappattachment": {
      "results": [
        {
          "__metadata": {
            "uri": "https://apisalesdemo8.successfactors.com:443/odata/v2/Attachment(1188L)",
            "type": "SFOData.Attachment"
          },
          "fileExtension": "jpeg",
          "fileName": "hp-hero-img.jpeg",
          "fileContent": "/9j/4AA"
        },
        {
          "__metadata": {
            "uri": "https://apisalesdemo8.successfactors.com:443/odata/v2/Attachment(1189L)",
            "type": "SFOData.Attachment"
          },
          "fileExtension": "jpeg",
          "fileName": "hp-content-bkgd-img.jpeg",
          "fileContent": "/9j/4AAQSk"
        }]}}}

我确实找到了很多处理数组的教程，但我在第一个标记“d”时就已经失败了。而且根本不需要所有的“_元数据”标记。

我创建了一个包含lastName等属性和一个集合附件的pojo。但我的代码在标记“d”或“_元数据”时总是失败

public class ResponseDataObject {


    private String lastName;
    private String address;
    private String cellPhone;
    private String firstName;
    private String city;
    private String country;
    private List<Attachment> attachments = new ArrayList<>();
    .....getters and setters

还有杰克逊的读者

    ObjectReader objectReader =
    mapper.readerFor(ResponseDataObject.class);
    ResponseDataObject dataObject = objectReader.readValue(file);

任何提示都将不胜感激。

问候马蒂亚斯

Answer 1

您需要忽略POJO中不存在的属性。在对象映射器的反序列化功能中设置以下属性：

// for version 1.x       
mapper.configure(DeserializationConfig.Feature.FAIL_ON_UNKNOWN_PROPERTIES, false);
// for newer versions
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false) 

反序列化代码：

ObjectMapper mapper = new ObjectMapper();
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
mapper.configure(DeserializationFeature.UNWRAP_ROOT_VALUE, true);
ResponseDataObject dataObject = mapper.readValue(file, ResponseDataObject.class);

并将此注释添加到ResponseDataObject类：

@JsonRootName(value = "d")
class ResponseDataObject {

Answer 2

您可以使用@JsonIgnoreProperties注释来忽略与类中定义的任何成员不匹配的属性，例如：

@JsonIgnoreProperties(ignoreUnknown = true)
public class ResponseDataObject {

这将确保映射所有匹配的属性，并忽略其他属性。