类型错误没有将符号隐式转换为整数

Question

搞砸

data = {
  :recordset => {
    :row => {
      :property => [
        {:name => "Code",     :value => "C0001"}, 
        {:name => "Customer", :value => "ROSSI MARIO"}
      ]
    }
  },
  :@xmlns => "http://localhost/test"
}

使用的代码

result = data[:recordset][:row].each_with_object([]) do |hash, out|
           out << hash[:property].each_with_object({}) do |h, o|
                    o[h[:name]] = h[:value]
                  end
         end

我无法获得以下输出:

[{"Code"=>"C0001", "Customer"=>"ROSSI MARIO", "Phone1"=>"1234567890"}

错误信息：

类型错误没有将符号隐式转换为整数

在多条记录的情况下，它可以正常工作

data = {
  :recordset => {
    :row => [{
      :property => [
        {:name => "Code",     :value => "C0001"},
        {:name => "Customer", :value => "ROSSI MARIO"},
        {:name => "Phone1",   :value => "1234567890"}
      ]
    }, {
      :property => [
        {:name => "Code",     :value => "C0002"},
        {:name => "Customer", :value => "VERDE VINCENT"},
        {:name => "Phone1",   :value => "9876543210"},
        {:name => "Phone2",   :value => "2468101214"}
      ]
    }]
  },
  :@xmlns => "http://localhost/test"
}

使用的代码

data.keys
#=> [:recordset, :@xmlns] 

data[:recordset][:row].count
#=> 2   # There are 2 set of attribute-value pairs


result = data[:recordset][:row].each_with_object([]) do |hash, out|
           out << hash[:property].each_with_object({}) do |h, o|
                    o[h[:name]] = h[:value]
                  end
         end
#=> [
#   {"Code"=>"C0001", "Customer"=>"ROSSI MARIO", "Phone1"=>"1234567890"},
#   {"Code"=>"C0002", "Customer"=>"VERDE VINCENT", "Phone1"=>"9876543210", "Phone2"=>"2468101214"}
# ] 

Answer 1

如果不是数组，则可以创建一个数组，以便在处理输入之前对其进行规范化。

info = data[:recordset][:row]
info = [info] unless info.is_an? Array
result = info.each_with_object([]) do ....

Answer 2

在第一种情况下，数据[：记录集][：行]不是一个数组，它是一个散列，因此当您迭代它时，Hash变量成为数组：

[:property, [{:name=>"Code", :value=>"C0001"}, {:name=>"Customer", :value=>"ROSSI MARIO"}]]

在第二种情况下，它是一个数组，而不是一个散列，所以当你迭代它时，它变成了散列:

{:property=>[{:name=>"Code", :value=>"C0001"}, {:name=>"Customer", :value=>"ROSSI MARIO"}, {:name=>"Phone1", :value=>"1234567890"}]}

你总是假设这是第二种格式。您可以将它强制放入一个数组中，然后展平1个级别，以同等对待这两个实例:

result = [data[:recordset][:row]].flatten(1).each_with_object([]) do |hash, out|
  out << hash[:property].each_with_object({}) do |h, o|
    o[h[:name]] = h[:value]
  end
end

# => [{"Code"=>"C0001", "Customer"=>"ROSSI MARIO"}] # result from example 1
# => [{"Code"=>"C0001", "Customer"=>"ROSSI MARIO", "Phone1"=>"1234567890"},
#     {"Code"=>"C0002", "Customer"=>"VERDE VINCENT",
#      "Phone1"=>"9876543210", "Phone2"=>"2468101214"}] # result from example 2

尝试使用Keral#Array（）而不是[]. flatten（1）是很有诱惑力的，但是您必须记住Hash实现了to_a来返回一个嵌套的键和值数组，所以Keral#Array（）不能像您希望的那样工作：

Array(data[:recordset][:row]) # using the first example data
# => [[:property, [{:name=>"Code", :value=>"C0001"}, {:name=>"Customer", :value=>"ROSSI MARIO"}]]]