AWS弹性豆茎上的Spring Boot/Tomcat仅显示404页

Question

<groupId>com.ideaEngine</groupId>
<artifactId>app_deployment</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>

<properties>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
    <project.reporting.outputEncoding>UTF-8</project.reporting.outputEncoding>
    <start-class>com.xxxxxxxx.WebappApplication</start-class>
    <java.version>1.8</java.version>
</properties>

<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-tomcat</artifactId>
    <scope>provided</scope>
</dependency>

Elastic Beanstalk服务器是64位Amazon Linux2016.03v2.2.0，运行Tomcat 8 Java 8

Localhost JVM是jdk1.8.0_71.jdk

申请对象为：

@SpringBootApplication
public class WebappApplication {

    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(WebappApplication.class);
    }

    public static void main(String[] args) {
        ApplicationContext ctx = SpringApplication.run(WebappApplication.class, args);
        System.out.println("Running............");
    }
}

@RestController
public class HelloController {

    @RequestMapping("/")
    public String index() {
        return "Greetings from Spring Boot!";
    }
}

我将。war文件命名为webapp.war和root.war，并尝试在.com/和/root/和/webapp/访问它

它们都生产404。

日志文件显示应用程序正在部署到服务器：

Deployment of web application directory /var/lib/tomcat8/webapps/ROOT has finished in 2,143 ms

Environment health has transitioned from Info to Ok. Application update completed 58 seconds ago and took 15 seconds.

你知道我错过了什么吗？

谢了！

Answer 1

所以我有一个类似的问题。我按照mkyong https://www.mkyong.com/spring-boot/spring-boot-deploy-war-file-to-tomcat/的说明进行操作，这似乎解决了我的问题。

查看您的代码，我注意到您的WebappApplication没有扩展SpringBootServletInitializer。也许可以尝试像这样扩展SpringBootServletInitializer。

@SpringBootApplication
public class WebappApplication extends SpringBootServletInitializer{

    @Override
    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
        return application.sources(WebappApplication.class);
    }

    public static void main(String[] args) {
        ApplicationContext ctx = SpringApplication.run(WebappApplication.class, args);
        System.out.println("Running............");
    }
}

那篇文章里都详述了。希望这能有所帮助！