正则表达式：按逗号拆分，但不包括括号和引号内的逗号（均为单引号）

Question

我有一根绳子

5,(5,5),C'A,B','A,B',',B','A,',"A,B",C"A,B" 

我想用逗号分隔，但需要排除括号和引号内的逗号（单引号和双引号）。

这样地

5（5,5）C'A，B' C'A，B'

使用java正则表达式如何实现这一点？？




Answer 1

考虑匹配，而不是拆分字符串。

String s  = "5,(5,5),C'A,B','A,B',',B','A,',\"A,B\",C\"A,B\"";
Pattern p = Pattern.compile("(?:[^,]*(['\"])[^'\"]*\\1|\\([^)]*\\))|[^,]+");
Matcher m = p.matcher(s);
while (m.find()) {
  System.out.println(m.group());
}

输出

5
(5,5)
C'A,B'
'A,B'
',B'
'A,'
"A,B" 
C"A,B"

Answer 2

,(?![^(]*\))(?![^"']*["'](?:[^"']*["'][^"']*["'])*[^"']*$)

试试这个。

见演示。

对于java

,(?![^(]*\\))(?![^"']*["'](?:[^"']*["'][^"']*["'])*[^"']*$)

Answer 3

你可以使用这个正则表达式：

String input = "5,(5,5),C'A,B','A,B',',B','A,',\"A,B\",C\"A,B\"";
String[] toks = input.split( 
                ",(?=(([^']*'){2})*[^']*$)(?=(([^\"]*\"){2})*[^\"]*$)(?![^()]*\\))" );
for (String tok: toks)
    System.out.printf("<%s>%n", tok);

输出：

<5>
<(5,5)>
<C'A,B'>
<'A,B'>
<',B'>
<'A,'>
<"A,B">
<C"A,B">

说明：

,                         # Match literal comma
(?=(([^']*'){2})*[^']*$)  # Lookahead to ensure comma is followed by even number of '
(?=(([^"]*"){2})*[^"]*$)  # Lookahead to ensure comma is followed by even number of "
(?![^()]*\\))             # Negative lookahead to ensure ) is not followed by matching
                          # all non [()] characters in between