如何获得日期在yyyy mm dd中的年份差异？

Question

我想得到以yyyy-mm-dd格式给出的两个日期之间的差值，差值应以年为单位。

        var ds='2002-09-23';
        var today_date = new Date();
        alert(today_date);
        Date.prototype.yyyymmdd = function() {
        var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
        var dd  = this.getDate().toString();
        var dt = yyyy +"-"+(mm[1]?mm:"0"+mm[0]) +"-"+ (dd[1]?dd:"0"+dd[0]);// padding
        var num_years = diff_date/31536000000;
        alert(num_years);
        if (num_years>18){
           alert (num_years);
        }else{
        alert ("i m not 18");
               }

请帮帮我。

Answer 1

请尝试以下代码以获得年份差异...

function getDateDiffInYears(date1, date2) {
  var dateParts1 = date1.split('-')
    , dateParts2 = date2.split('-')
    , d1 = new Date(dateParts1[0], dateParts1[1]-1, dateParts1[2])
    , d2 = new Date(dateParts2[0], dateParts2[1]-1, dateParts2[2])

  return new Date(d2 - d1).getYear() - new Date(0).getYear() + 1;
}

var diff = getDateDiffInYears('2005-09-23', '2012-07-3');

console.log(diff); // => 7 years

祝你好运

Answer 2

这不需要库，只需要纯javascript：

function wholeYearsBetweenTwoDates(dateOneString, dateTwoString) {
    // assuming that dateTwo is later in time than dateOne
    var dateOne = getDateFromString(dateOneString);
    var dateTwo = getDateFromString(dateTwoString);

    var result = dateTwo.getFullYear() - dateOne.getFullYear();

    dateOne.setFullYear(dateTwo.getFullYear());
    if (dateOne > dateTwo) {
        // compensate for the case when last year is not full - e.g., when
        // provided with '2009-10-10' and '2010-10-09', this will return 0
        result -= 1;
    }

    return result;
}

function getDateFromString(stringDate) {
    var dateParts = stringDate.split('-');
    var result = new Date(dateParts[0], dateParts[1], dateParts[2]);
    return result;
}

Answer 3

这要短得多：

var yearsApart = new Date(new Date - new Date('2002-09-23')).getFullYear()-1970

…但是要小心，通过提供正确的日期时间字符串来处理非UTC时区！