无法通过Android解析从Facebook登录获得性别

Question

我遵循了parse的教程，并根据他们的指导方针配置了我的FB开发人员帐户以及所需的包名和哈希键。在权限，我已经要求用户配置文件和电子邮件id，所以我应该得到他们的脸书id，全名，性别和电子邮件id作为脸书dcumentation。

我正在返回这个JSON。性别和电子邮件id不是以null值作为键的事件。当然，我已经覆盖了我的FB id。{“名称”：“Varun Agarwal”，“ID”：“11111111111111111”}

public void onLoginClick(View v) {
    progressDialog = ProgressDialog.show(LoginActivity.this, "", "Logging in...", true);

    List<String> permissions = Arrays.asList("public_profile", "email");
    // NOTE: for extended permissions, like "user_about_me", your app must be reviewed by the Facebook team
    // (https://developers.facebook.com/docs/facebook-login/permissions/)

    ParseFacebookUtils.logInWithReadPermissionsInBackground(this, permissions, new LogInCallback() {
      @Override
      public void done(ParseUser user, ParseException err) {
        progressDialog.dismiss();
        if (user == null) {
          Log.d(IntegratingFacebookTutorialApplication.TAG, "Uh oh. The user cancelled the Facebook login.");
        } else if (user.isNew()) {
          Log.d(IntegratingFacebookTutorialApplication.TAG, "User signed up and logged in through Facebook!");
          showUserDetailsActivity();
        } else {
          Log.d(IntegratingFacebookTutorialApplication.TAG, "User logged in through Facebook!");
          showUserDetailsActivity();
        }
      }
    });
  }

 private void makeMeRequest() {
    GraphRequest request = GraphRequest.newMeRequest(AccessToken.getCurrentAccessToken(),
            new GraphRequest.GraphJSONObjectCallback() {
              @Override
              public void onCompleted(JSONObject jsonObject, GraphResponse graphResponse) {
                if (jsonObject != null) {
                  JSONObject userProfile = new JSONObject();
                    Log.d("Data", jsonObject.toString());

                  try {
                    userProfile.put("facebookId", jsonObject.getLong("id"));
                    userProfile.put("name", jsonObject.getString("name"));

                    if (jsonObject.getString("gender") != null)
                      userProfile.put("gender", jsonObject.getString("gender"));

                    if (jsonObject.getString("email") != null)
                      userProfile.put("email", jsonObject.getString("email"));

                    // Save the user profile info in a user property
                    ParseUser currentUser = ParseUser.getCurrentUser();
                    currentUser.put("profile", userProfile);
                    currentUser.saveInBackground();

                    // Show the user info
                    updateViewsWithProfileInfo();
                  } catch (JSONException e) {
                    Log.d(IntegratingFacebookTutorialApplication.TAG,
                            "Error parsing returned user data. " + e);
                  }
                } else if (graphResponse.getError() != null) {
                  switch (graphResponse.getError().getCategory()) {
                    case LOGIN_RECOVERABLE:
                      Log.d(IntegratingFacebookTutorialApplication.TAG,
                              "Authentication error: " + graphResponse.getError());
                      break;

                    case TRANSIENT:
                      Log.d(IntegratingFacebookTutorialApplication.TAG,
                              "Transient error. Try again. " + graphResponse.getError());
                      break;

                    case OTHER:
                      Log.d(IntegratingFacebookTutorialApplication.TAG,
                              "Some other error: " + graphResponse.getError());
                      break;
                  }
                }
              }
            });

    request.executeAsync();
  }

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    makeMeRequest(); ---------> }

Answer 1

尝试使用graphResponse代替JSONObject。

public void onCompleted(JSONObject jsonObject, GraphResponse graphResponse) 
{
    response.getJSONObject().getString("email")
    response.getJSONObject().getString("gender")
    response.getJSONObject().getString("id")
    response.getJSONObject().getString("name")
}