如何使用OnListItemClickListener使用此搜索过滤ListView

Question

我在使用 setOnItemClickListener 时遇到问题。每次我尝试时，它都会导致太多的修复错误，使代码比我打算做的更糟糕。

这是我的代码:

public class Search extends Activity{
// List view
private ListView lv;

// Listview Adapter
ArrayAdapter<String> adapter;

// Search EditText
EditText inputSearch;


// ArrayList for Listview
ArrayList<HashMap<String, String>> productList;

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_search);

// Listview Data
final String products[] = {"Fill in the Blocks", "The Music Bee", "Little Paragon",
"Subway Surfers", "Cytus", "Temple Run", "Clumsy Ninja", "Smash Hit"};

lv = (ListView) findViewById(R.id.list_view);
inputSearch = (EditText) findViewById(R.id.inputSearch);

// Adding items to listview
adapter = new ArrayAdapter<String>(this, R.layout.list_item, R.id.product_name,        products);
lv.setAdapter(adapter);

/**
* Enabling Search Filter
* */
inputSearch.addTextChangedListener(new TextWatcher() {

@Override
public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
// When user changed the Text
Search.this.adapter.getFilter().filter(cs);   
}
@Override
public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,
int arg3) {
// TODO Auto-generated method stub       
}

@Override
public void afterTextChanged(Editable arg0) {
// TODO Auto-generated method stub                          
}            
});    
}       
}

我想让listview数据中的字符串在我的其他活动中可点击，但这不起作用。我试过这个代码:

 lv.setOnItemClickListener(new OnItemClickListener() {
 public void onItemClick(AdapterView<?> parent, View view, int position, long id) {

 String openClass = adapter.getItem[position];
 if (openClass.equals("Fill in the Blocks")) {
   Intent myIntent = new Intent(view.getContext(), Fill_in_the_Blocks.class);
   startActivityForResult(myIntent, 0);
   }
 else if (openClass.equals("The Music Bee")) {
   Intent myIntent1 = new Intent(view.getContext(), The_Music_Bee.class);
   startActivityForResult(myIntent1, 0);
   }
 else if (openClass.equals("Little Paragon")) {
   Intent myIntent2 = new Intent(view.getContext(), Little_Paragon.class);
   startActivityForResult(myIntent2, 0);
   }
   }

错误如下：-在lv.setOnItemClickListener中，“AdapterView类型中的方法setOnItemClickListener（AdapterView.OnItemClickListener）不适用于参数（new OnItemClickListener(){})" -在（new OnItemClickListener（）中，“OnItemClickListener无法解析为类型”-在公共空隙中onItemClick（AdapterView，“AdapterView无法解析为类型”-在字符串openClass=adapter.getItem[位置]中；，“getItem无法解析或不是字段”

Answer 1

• 在lv.setOnItemClickListener中，"AdapterView类型中的方法setOnItemClickListener（AdapterView.OnItemClickListener）不适用于参数（new OnItemClickListener(){})"
• 在（new OnItemClickListener（）中，“OnItemClickListener无法解析为类型”
• 在公共无效onItemClick（AdapterView，“AdapterView不能解析为类型”

通过将新的OnItemClickListener（）替换为

new AdapterView.OnItemClickListener()

并确保您导入了:

import android.widget.AdapterView;

最后一个错误：

< li >在字符串open class = adapter . getitem[position]中；，“getItem无法解析或不是字段”

您应该调用getItem方法，而不是使用数组索引。

替换行：

String openClass = adapter.getItem[position];

跟

String openClass = adapter.getItem(position);