将JSON转换为guzzle php librairy请求

Question

我试图隐藏一个卷曲来吞咽请求，这里是卷曲请求。

curl https://{subdomain}.zendesk.com/api/v2/tickets.json \
  -d '{"ticket": {"subject": "My printer is on fire!", "comment": { "body": "The smoke is very colorful." }}}' \
  -H "Content-Type: application/json" -v -u {email_address}:{password} -X POST

以下是JSON部分：

{
    "ticket": {
        "requester": {
            "name": "The Customer",
            "email": "[e-mail]"
        },
        "subject": "My printer is on fire!",
        "comment": {
            "body": "The smoke is very colorful."
        }
    }
}

$client = new GuzzleHttp\Client();

$res = $client->post('https://midnetworkshelp.zendesk.com/api/v2/tickets/tickets.json', [

            'query' => [

                     'ticket' => ['subject' => 'My print is on Fire'], [ 

                     'comment' => [

                                'body' => 'The smoke is very colorful'] ],  'auth' =>  ['email', 'Password']]);

echo $res->getBody();

Answer 1

参考：

1. http://curl.haxx.se/docs/manpage.html
2. http://guzzle.readthedocs.org/en/latest/clients.html
3. https://github.com/guzzle/log-subscriber
4. http://guzzle.readthedocs.org/en/latest/clients.html#json

您最大的问题是您没有正确地转换curl请求。

null

$client = new GuzzleHttp\Client([
        'base_url'      => ['https://{subdomain}.zendesk.com/api/{version}/', [
                'subdomain'     => '<some subdomain name>',
                'version'       => 'v2',
        ],
        'defaults'      => [
                'auth'  => [ $username, $password],
                'headers' => ['Content-Type' => 'application/json'],    //only if all requests will be with json
        ],
        'debug'         => true,                                        // only for debugging purposes
]);

1. 确保向api发出的多个后续请求将具有身份验证信息。使您不必将其添加到每个请求中。
2. 确保用此客户端发出的multipl后续（实际上是所有）请求将包含指定的标头。使您不必将其添加到每个请求中。
3. 提供一定程度的将来校对（将子域和api版本移到可编辑字段中）。

如果选择记录请求和响应对象，还可以执行以下操作：

// You can use any PSR3 compliant logger in space of "null".
// Log the full request and response messages using echo() calls.
$client->getEmitter()->attach(new GuzzleHttp\Subscriber\Log\LogSubscriber(null, GuzzleHttp\Subscriber\Log\Formatter::DEBUG);

您的请求将简单地变成：

$json = '{"ticket": {"subject": "My printer is on fire!", "comment": { "body": "The smoke is very colorful." }}}';
$url = 'tickets/tickets.json';

$request = $client->createRequest('POST', $url, [
        'body' => $json,
]);
$response = $client->send($request);

$json = '{"ticket": {"subject": "My printer is on fire!", "comment": { "body": "The smoke is very colorful." }}}';
$url = 'tickets/tickets.json';

$result = $client->post(, [
        'body'  => $json,
]);

编辑：在进一步阅读参考文献4之后，应该可以做以下几点：

$url = 'tickets/tickets.json';
$client = new GuzzleHttp\Client([
    'base_url'      => ['https://{subdomain}.zendesk.com/api/{version}/', [
        'subdomain'     => '<some subdomain name>',
        'version'       => 'v2',
    ],
    'defaults'      => [
        'auth'  => [ $username, $password],
    ],
    'debug'         => true,                                        // only for debugging purposes
]);
$result = $client->post($url, [
    'json' => $json,            // Any PHP type that can be operated on by PHP’s json_encode() function.
]);