jar的Url问题

Question

抱歉，如果在西班牙语中“no existe el archivo o el directorio”表示“不存在这样的文件或目录”。

/home/user1/netbeansprojects/project1/dist/project1.jar！/music/2.wav线程“thread-0”java.lang.illegalstateexception:java.io.fileNotFoundException://home/user1/netbeansprojects/project1/dist/project1.jar！/music/2.wav（No existe el archivo o el directorio）在logic.audiofileplayer.run（audiofileplayer.java:54)上的directorio）在java.io.fileInputStream.open（本机方法）在java.io.fileInputStream.（fileInputStream.java:146)在com.sun.media.sound.waveFloatFileReader.getAudioInputStream（waveFloatFileReader.java:164)在javax.sound.sampled.audioSystem.getAudioInputStream（audioSystem.java:1179)在logic.audioFilePlayer.run（

代码如下：

boolean loop = true;
private final URL url = getClass().getResource("/music/2.wav");
private final String convertFilePath = url.toString();
String filePath = convertFilePath.substring(convertFilePath.lastIndexOf("file:") + 5);

@Override
public void run() {
    while (loop == true) {
        final File file = new File(filePath);
        System.out.println(filePath);
        try (final AudioInputStream in = getAudioInputStream(file)) {

            final AudioFormat outFormat = getOutFormat(in.getFormat());
            final Info info = new Info(SourceDataLine.class, outFormat);

            try (final SourceDataLine line
                    = (SourceDataLine) AudioSystem.getLine(info)) {

                if (line != null) {
                    line.open(outFormat);
                    line.start();
                    stream(getAudioInputStream(outFormat, in), line);
                    line.drain();
                    line.stop();
                }
            }

        } catch (UnsupportedAudioFileException | LineUnavailableException | IOException e) {
            throw new IllegalStateException(e);
        }
    }
}

private AudioFormat getOutFormat(AudioFormat inFormat) {
    final int ch = inFormat.getChannels();
    final float rate = inFormat.getSampleRate();
    return new AudioFormat(PCM_SIGNED, rate, 16, ch, ch * 2, rate, false);
}

private void stream(AudioInputStream in, SourceDataLine line)
        throws IOException {
    final byte[] buffer = new byte[4096];
    for (int n = 0; n != -1; n = in.read(buffer, 0, buffer.length)) {
        line.write(buffer, 0, n);
    }
}

Answer 1

在使用JAR时，您应该处理jar:fileURL，而不是自己操作它并尝试创建file对象。如果构造函数支持，则应将从getresource获得的URL直接传递给构造函数。

// get the URL of the file as usual
URL url = getClass().getResource("/music/2.wav");

// get stream directly from URL, which could be a file or a jar:file
AudioInputStream in = getAudioInputStream(url);

如果这不起作用，并且库可以接受输入流，那么可以尝试使用ClassLoader#GetResourceAsstream并将其传递给适当的构造函数/方法。

否则，您可以尝试将文件解压缩到本地的某个位置，然后传递该文件的路径。