android:窗口管理器:Android查看窗口泄露[重复]

Question

就在我解决了我的第一个问题之后，这个问题出现了：（请帮我解决它...

03-02 12:47:02.785 9439-9439/com . ucu . CCS . class record E/window manager￡Android . view . window leaved:Activity com . ucu . CCS . class record . log in已泄漏window com . Android . internal . policy . impl . phone window $ dec view { 6d 17 cc 4V . E.....稀有......D 0，0-1002，348}最初添加在此处的Android . view . viewrootimpl .(viewrootimpl . Java:465)在Android . view . windowmanager global . add view(windowmanager global . Java:277)在Android . view . windowmanager impl . add view(windowmanager impl . Java:69)在Android . app . dialog . show(dialog . Java:312)在com . ucu . CCS . class record . log in＄attemptlogin . onpree

以下是我的代码:

buttonLogin.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String instructor_id = editUser.getText().toString().trim();
                String password = editPass.getText().toString().trim();

                SharedPreferences preferences = getSharedPreferences("MyApp", MODE_PRIVATE);
                preferences.edit().putString("password", password).commit();
                preferences.edit().putString("inst_id", instructor_id).commit();

                if (editUser.getText().toString().equals("") || editPass.getText().toString().equals("")){
                    Toast.makeText(getApplicationContext(),"Please enter Instructor ID and Password", Toast.LENGTH_LONG).show();
                }else {
                    isOnline();
                }

            }
        });

public boolean isOnline(){
        ConnectivityManager connectivityManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
        if (networkInfo != null && networkInfo.isConnectedOrConnecting()){
            new AttemptLogin().execute();
        }else {
            checkInternet();
        }
        return false;
    }

class AttemptLogin extends AsyncTask<String, String, String> {
        boolean failure = false;
        String inst_id = editUser.getText().toString();
        String password = editPass.getText().toString();

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            pDialog = new ProgressDialog(Login.this);
            pDialog.setMessage("Attempting login...");
            pDialog.setIndeterminate(false);
            pDialog.setCancelable(true);
            pDialog.show();
        }

        @Override
        protected String doInBackground(String... params) {
            int success;
            try{
                List<NameValuePair> mList = new ArrayList<NameValuePair>();
                mList.add(new BasicNameValuePair("instructor_id", inst_id));
                mList.add(new BasicNameValuePair("password", password));

                Log.d("request!", "starting");

                JSONObject json = jsonParser.makeHttpRequest(LOGIN_URL, "POST", mList);
                Log.d("Login attempt", json.toString());

                success = json.getInt(TAG_SUCCESS);
                if (success == 1) {
                    Log.d("Login Successful!", json.toString());
                    Intent i = new Intent(Login.this, MainActivity.class);
                    startActivity(i);
                    //finish();
                    return json.getString(TAG_MESSAGE);
                }else{
                    Log.d("Login Failure!", json.getString(TAG_MESSAGE));
                    return json.getString(TAG_MESSAGE);
                }

            }catch (JSONException e){
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            session.setLogin(true);
            pDialog.dismiss();
            if (s != null){
                Toast.makeText(getApplicationContext(), s, Toast.LENGTH_SHORT).show();
            }
        }
    }

Answer 1

实际上，您的活动在某种程度上已经完成，因此您需要关闭对话。

在onPause（）中，添加以下代码：

if(isFinishing()){
    if (pDialog!= null) {
        pDialog.dismiss();
        pDialog= null;
    }
}

Answer 2

您试图在退出活动后显示一个对话框。在您的doInbackground中，当您移动活动时，请在开始活动（i）之前关闭对话框，试试这个，让我知道它是否有效。