Apache Camel-需要递归地读取文件

Question

    <route>
        <!--  Reading from MDW REST url -->
        <from uri="mdw:REST/REST" />
        <!--  Parsing OrderNumber and OrderVersion-->
        <setHeader headerName="OrderNumber">
            <xpath>Some path</xpath>
        </setHeader>
        <setHeader headerName="OrderVersion">
            <xpath>Some path</xpath>
        </setHeader>
        <!-- Request being put in file folder -->
        <to
            uri="file:data/inbox?fileName=${header.OrderNumber}-${header.OrderVersion}.xml"
            pattern="InOut" />
    </route>
    <!-- route with when clause: Checks memory consumption before putting message 
        on queue. If consumption below threshold put on queue
        else put back into input folderk-->
    <route>
        <from uri="file:data/inbox" />
        <camel:process ref="checkMemoryConsumption" />
        <camel:when>
        <!-- If  -->
            <camel:simple>${in.header.result} == 'true'</camel:simple>
            <camel:convertBodyTo type="String" />
            <to uri="jms queue"
                pattern="InOut" />
        </camel:when>
        <camel:when>
            <camel:simple>${in.header.result} == 'false'</camel:simple>
            <camel:convertBodyTo type="String" />
            <to uri="file:data/inbox"  pattern="InOut" />
        </camel:when>
    </route>

<camel:route>
<camel:from uri="file:data/inbox"/>
<camel:filter>
    <method ref="checkMemory" method="isFreeMemoryAboveSafeLimit"/>
    <to uri="jms:queue:com.centurylink.mdw.external.event.queue"
            pattern="InOut" />
</camel:filter>

Answer 1

也许可以使用一个文件过滤器，在其中检查内存消耗，并返回true false是否要接受该文件。那么您就不需要在路由中添加该选项。

请参阅筛选器选项

• http://camel.apache.org/file2