通过xslt使用从xml到文本文件的转换时引发异常

Question

我的代码如下所示：

  protected String[] parseXMLRecievedMsg(StringBuffer iSB_plainMessage) throws Exception {

    Source xslt = new StreamSource(new File("sample.xslt"));
    TransformerFactory transFact = TransformerFactory.newInstance();
    Transformer transformer = transFact.newTransformer(xslt);
    StringWriter outWriter = new StringWriter();
    StreamResult lS_outputMsgBody = new StreamResult( outWriter );
    iSB_plainMessage =iSB_plainMessage.delete(0,iSB_plainMessage.indexOf("\n"));
    iSB_plainMessage =iSB_plainMessage.reverse();
    iSB_plainMessage =iSB_plainMessage.delete(0, iSB_plainMessage.indexOf("\n"));
    iSB_plainMessage =iSB_plainMessage.reverse();
    StringBuilder SB_plainMessage = new StringBuilder(iSB_plainMessage.toString());
    SB_plainMessage.insert(0,"<?xml version=\"1.0\" encoding=\"UTF-8\"?>\r");

    Source lSB_MessageInput = new StreamSource(SB_plainMessage.toString());
    transformer.setOutputProperty(OutputKeys.METHOD, "text");
    transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");




    transformer.transform(lSB_MessageInput, lS_outputMsgBody);

    return new String []{ lS_outputMsgBody.getWriter().toString()};

`

java.io.FileNotFoundException：c:\alltra_apps\bic\base_domain\allNetTimPort\（文件名、目录名或卷标语法不正确）在java.io.FileInputStream.Open（本机方法）在java.io.FileInputStream。（FileInputStream.java:120)在java.io.FileInputStream。（FileInputStream.java:79)在sun.net.www.protocol.file.fileUrlConnection.connect（OM.sun.org.apache.xalan.internal.xsltc.dom.xsltcdtmmanager.getDTM（xsltcdtmmanager.java:234)在com.sun.org.apache.xalan.internal.xsltc.trax.transformerimpl.getDOM（transformerimpl.java:524)在

Answer 1

StreamSource构造函数的重载使用String(https://docs.oracle.com/javase/8/docs/api/javax/XML/transform/stream/streamSource.html#streamSource-java.lang.String-)需要一个带有URI的String，而您似乎传递了一个带有动态构造的XML的字符串。如果要用XML读取字符串,则在字符串上的StringReader上构造StreamSource。