JAXB生成的xml中的“xsi：type”和“xmlns：xsi”

Question

@XmlRootElement
public class Root {

    @XmlAttribute
    private String path;

    @XmlElement(name = "dir")
    private ArrayList<Dir> rootContentDirs = null;

    @XmlElement(name = "file")
    private ArrayList<FileObj> rootContentFiles = null;


    public void setRootContentDirs(ArrayList<Dir> rootContentDirs) {
        this.rootContentDirs = rootContentDirs;
    }

    public void setRootContentFiles(ArrayList<FileObj> rootContentFiles) {
        this.rootContentFiles = rootContentFiles;
    }

    public void setPath(String path) {
        this.path = path;
    }
 }

public class Dir {

    @XmlAttribute
    private String name;

    @XmlElement(name = "dir")
    private ArrayList dirs = null;

    @XmlElement(name = "file")
    private ArrayList files = null;

    public void setName(String name) {
        this.name = name;
    }

    public void setDirs(ArrayList dirs) {
        this.dirs = dirs;
    }

    public void setFiles(ArrayList files) {
        this.files = files;
    }
 }

public class FileObj{

   @XmlAttribute
   private String name;
   @XmlAttribute
   private long size;
   @XmlAttribute
   private String type;


   public void setName(String name) {
       this.name = name;
   }

   public void setSize(long size) {
       this.size = size;
   }

   public void setType(String type) {
       this.type = type;
   }
}

public class XmlByJaxb extends Generator {

private static final String JAXB_XML = "./jaxb.xml";
private static Root root = null;

@Override
public void output() throws IOException {
    JAXBContext context = null;
    Marshaller m = null;
    try {
        context = JAXBContext.newInstance(Root.class, Dir.class, FileObj.class);
        m = context.createMarshaller();
        m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
        m.marshal(root, new File(JAXB_XML));
    } catch (JAXBException e) {

    }
}

@Override
public void run() {
    ArrayList<FileObj> rootFiles = addFiles(dir);
    ArrayList<Dir> rootDirs = make(dir);

    root = new Root();
    root.setPath(dir.getPath());
    root.setRootContentFiles(rootFiles);
    root.setRootContentDirs(rootDirs);
/.../
}

但是我在生成的XML中有奇怪的“xsi：type”和“xmlns：xsi”：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root path="/home/phlamey/IdeaProjects/FileUtillite">
<dir name="src">
    <dir xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="dir" name="test">
        <dir xsi:type="dir" name="java">
            /.../ 

所以我的问题是：这是什么意思，如何删除它？

Answer 1

在dir类中，您没有指定集合的类型，这就是JAXB添加xsi:type属性的原因。

您有：

@XmlElement(name = "dir")
private ArrayList dirs;

如果ArrayList将包含DIR的实例，则可以执行以下操作：

@XmlElement(name = "dir")
private ArrayList<Dir> dirs = null;

@XmlElement(name = "dir", type=Dir.class)
private ArrayList dirs = null;