Java方法和调用方法的次数过多

Question

我在使用Java方法时遇到了麻烦。这段代码应该有三种方法。方法1）输入员工人数。方法2）输入每个员工缺勤天数。方法3）计算缺勤天数的平均值。然后，在Main中，应该打印员工人数、缺勤天数和平均缺勤天数。显然，我不明白方法是如何工作的，因为当我运行代码时，用户在提供员工人数、缺勤天数和平均缺勤天数之前，会被询问4倍的员工人数和2倍的员工缺勤天数。如何更改代码，以便用户只需输入一次信息？

public static void main(String[] args) {
    /** Asks for the # of employees and their days absent using
     3 methods. 1) Requests number of employees, 2) # of days absent, 3)
     Average # of days absent)*/

    int numEmployeeM, numDaysMissedM;
    double averageNumDaysAbsentM;

    numEmployeeM = numEmployee();
    numDaysMissedM = numDaysMissed(numEmployeeM);
    averageNumDaysAbsentM = averageNumDaysAbsent(numEmployeeM,
            numDaysMissedM);
    System.out.println("\n\tTotal number of employees: " + numEmployeeM +
            "\n\tTotal number of days missed: " + numDaysMissedM +
            "\n\tAverage number of days absent: " + averageNumDaysAbsentM);
}

public static int numEmployee() {
    Scanner keyboard = new Scanner(System.in);

    int numEmployee;

    System.out.print("Number of employees in company:");
    numEmployee = keyboard.nextInt();
    return numEmployee;
}

public static int numDaysMissed(int numEmployee1) {
    Scanner keyboard = new Scanner(System.in);

    int count, numDaysMissed, totalNumDaysMissed;
    count = 1;
    totalNumDaysMissed = 0;
    numEmployee1 = numEmployee();

    while (count <= numEmployee1) {
        System.out.print("Enter number of days missed by Employee #"
                + count + ": ");
        numDaysMissed = keyboard.nextInt();
        totalNumDaysMissed += numDaysMissed;
        count++;
    }
    return totalNumDaysMissed;
}

public static double averageNumDaysAbsent(int numEmployee2,
                                          int totalNumDaysMissed1) {
    double averageDaysMissed;
    numEmployee2 = numEmployee();
    totalNumDaysMissed1 = numDaysMissed(numEmployee2);

    averageDaysMissed = (totalNumDaysMissed1 / numEmployee2);
    return averageDaysMissed;
}

Answer 1

简化代码以查看什么调用什么：

void main(String[] args)
{
    numEmployeeM = numEmployee();
    numDaysMissedM = numDaysMissed(numEmployeeM);
    averageNumDaysAbsentM = averageNumDaysAbsent(numEmployeeM, numDaysMissedM);
}

int numEmployee()
{
}

int numDaysMissed(int numEmployee1)
{
    numEmployee1 = numEmployee();
}

double averageNumDaysAbsent(int numEmployee2, int totalNumDaysMissed1)
{
    numEmployee2 = numEmployee();
    totalNumDaysMissed1 = numDaysMissed(numEmployee2);
}

所以当你的代码执行时，它会调用

• 主要的
  • 新员工
  • numDaysMissed
    • 新兵
    • Nume
    • 未接
      • Nume

      这给出了预期的总计数为1x平均数NumDaysAbent，2xNumDaysMisse和4xNum雇员

      在numDaysMissed和averageNumDaysAbsent中，您正在覆盖输入参数，使它们变得无用

      试着去掉这些线，它应该会像预期的那样工作