如何对HTML转义符号进行改型？

Question

public class RestClientFactory {
    private static GsonBuilder gsonBuilder = GsonUtil.gsonbuilder;
    private static Gson gson;
    private static OkHttpClient.Builder httpClient;
    private static HttpLoggingInterceptor httpLoggingInterceptor 
        = new HttpLoggingInterceptor()
            .setLevel(HttpLoggingInterceptor.Level.BASIC);

    static {
       gsonBuilder.setDateFormat(DateUtil.DATETIME_FORMAT);
        httpClient = new OkHttpClient.Builder();
        gson = gsonBuilder.create();
    }

    private static Retrofit.Builder builder = new Retrofit.Builder()
            .baseUrl(BuildConfig.API_BASE_URL)
            .addConverterFactory(GsonConverterFactory.create(gson))
            .client(httpClient.build());

    private static Retrofit retrofit = builder.build();
}

如果传入的JSON中有任何HTML转义符号，例如&；，referfit并不是不转义它。

例如。当传入的json有文本时：

希尔赫&安培；合身

Answer 1

作为一个通用的解决方案，这可以通过自定义JSONDESERIALISER来完成，例如：

public class HtmlAdapter implements JsonDeserializer<String> {

    @Override
    public String deserialize(JsonElement json, Type typeOfT, 
                                  JsonDeserializationContext context)
        throws JsonParseException {
        return StringEscapeUtils.unescapeHtml4(json.getAsString());
    }

}

并添加

gsonBuilder.registerTypeAdapter(String.class, new HtmlAdapter())

到你的静态块。方法stringescapeutils.unescapehtml4来自外部库org.apache.commons，commons-text，但是您可以使用任何感觉更好的方法。