mysql保持并等待相同的锁

Question

------------------------
LATEST DETECTED DEADLOCK
------------------------
2018-08-15 05:58:56 7fdff5872700
*** (1) TRANSACTION:
TRANSACTION 81567872, ACTIVE 0 sec inserting
mysql tables in use 1, locked 1
LOCK WAIT 4 lock struct(s), heap size 1184, 2 row lock(s), undo log entries 2
MySQL thread id 455326, OS thread handle 0x7fdff9083700, query id 255309181 10.8.201.34 slnbdata update
INSERT INTO XXX

*** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 8065 page no 11084 n bits 192 index `PRIMARY` of table `XXX` trx id 81567872 lock_mode X insert intention waiting
Record lock, heap no 1 PHYSICAL RECORD: n_fields 1; compact format; info bits 0
 0: len 8; hex 73757072656d756d; asc supremum;;

*** (2) TRANSACTION:
TRANSACTION 81567879, ACTIVE 0 sec inserting
mysql tables in use 1, locked 1
4 lock struct(s), heap size 1184, 2 row lock(s), undo log entries 2
MySQL thread id 455338, OS thread handle 0x7fdff5872700, query id 255309187 10.8.201.34 slnbdata update
INSERT INTO XXX

*** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 8065 page no 11084 n bits 192 index `PRIMARY` of table `XXX` trx id 81567879 lock_mode X
Record lock, heap no 1 PHYSICAL RECORD: n_fields 1; compact format; info bits 0
 0: len 8; hex 73757072656d756d; asc supremum;;

*** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 8065 page no 11084 n bits 192 index `PRIMARY` of table `XXX` trx id 81567879 lock_mode X insert intention waiting
Record lock, heap no 1 PHYSICAL RECORD: n_fields 1; compact format; info bits 0
 0: len 8; hex 73757072656d756d; asc supremum;;

*** WE ROLL BACK TRANSACTION (2)
------------
TRANSACTIONS
------------

There do have a query before the insert:
SELECT
    pk_1,
    max(pk_2)
FROM
    table
WHERE
    pk_1 IN (...)
GROUP BY
    pk_1
but no queries between each insert.
And let me correct my reply above, the insert statement is:
insert into table_name(pk_1,pk_2 ...) values (1,1_1 ...) and insert into table_name(pk_1,pk_2 ...) values (2,2_1 ...)
We use foreach of mybatis like this:
   <insert id="save">
        <foreach collection="list" item="item" separator=";">
            INSERT INTO ...

CREATE TABLE `customer_address_info` (
  `customer_no` char(10) NOT NULL,
  `addr_index` int(1) unsigned NOT NULL,
  `addr_type` tinyint(1) NOT NULL,
  `province_code` char(6) DEFAULT NULL,
  `province_name` varchar(20) DEFAULT NULL,
  `city_code` char(6) DEFAULT NULL,
  `city_name` varchar(50) DEFAULT NULL,
  `county_code` char(6) DEFAULT NULL,
  `county_name` varchar(100) DEFAULT NULL,
  `zip_code` char(6) DEFAULT NULL,
  `detail` varchar(100) NOT NULL,
  `status` tinyint(4) unsigned NOT NULL,
  `create_date` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `create_user` varchar(30) NOT NULL,
  `modify_date` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP,
  `modify_user` varchar(30) DEFAULT NULL,
  PRIMARY KEY (`customer_no`,`addr_index`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

Answer 1

正如我所评论的，张贴的信息不足以看到全貌和了解真正的原因。我只会分享我的两分钱。

Show ENGINE INNODB状态指示每个转换都锁定了两行，并且有两个挂起的提交更改（2个行锁，undo log entries 2)，因此同一事务中应该有其他语句，但没有显示。

事务1正在等待IX锁，这防止了由X锁由事务2保持；事务2正在等待事务1持有的IX锁。

可以通过从表中选择*获取IX进行更新。OP添加的select语句是一个简单的select语句，不需要锁。