Firebase -当用户单击通知时，活动重新启动

Question

我正在编写一个使用fire base来实现通知的应用程序。在我的Mainactive中，我有一个带有一些url的WebView，但问题是当用户单击通知时，我想在WebView中使用不同的url打开MainActiviy。我读了很多，我在意图中添加了一个捆绑包（在单击通知时打开Mainactive），它会生成所需的url。但是当我单击通知时，Mainactive会重新启动，我的意思是，它不会转到onNewIntent，而是在创建上运行。这就是我实现它的方式：

private void sendNotification(String messageTitle, String messageBody, String url){

    Intent intent = new Intent(this, MainActivity.class);
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);

    //This adds the url to the intent
    if(!url.equals("")){
        Bundle bundle = new Bundle();
        bundle.putString("url", url);
        intent.putExtras(bundle);
    }

    PendingIntent pendingIntent = PendingIntent.getActivity(this, 0,intent, PendingIntent.FLAG_ONE_SHOT);

    String channelId = getString(R.string.default_notification_channel_id);

    NotificationCompat.Builder notificationBuilder = new NotificationCompat
            .Builder(this, channelId)
            .setContentTitle(messageTitle)
            .setContentText(messageBody)
            .setPriority(NotificationCompat.PRIORITY_DEFAULT)
            .setAutoCancel(true)
            .setSmallIcon(R.drawable.ic_launcher_background)
            .setContentIntent(pendingIntent);

    NotificationManager notificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);

    if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.O){
        NotificationChannel channel = new NotificationChannel(channelId,
                "Notification channel",
                NotificationManager.IMPORTANCE_DEFAULT);
        notificationManager.createNotificationChannel(channel);
    }

    notificationManager.notify(0, notificationBuilder.build());

}

onNewIntent我有这个：

Bundle bundle = intent.getExtras();
        if (bundle != null) {
            String url = bundle.getString("url");
            mWebView.loadUrl(url);
        }

但是，当单击通知时，活动只是重新启动，因此它不会在NewIntent上运行，并且日志会给我以下错误：

02-08 12:51:12.140 19056-19056/com.example.android.app E/ActivityThread: Activity com.example.android.app.MainActivity has leaked IntentReceiver com.example.android.app.MainActivity$1@d7818db that was originally registered here. Are you missing a call to unregisterReceiver()?
android.app.IntentReceiverLeaked: Activity com.example.android.app.MainActivity has leaked IntentReceiver com.example.android.app.MainActivity$1@d7818db that was originally registered here. Are you missing a call to unregisterReceiver()?
    at android.app.LoadedApk$ReceiverDispatcher.<init>(LoadedApk.java:999)
    at android.app.LoadedApk.getReceiverDispatcher(LoadedApk.java:795)
    at android.app.ContextImpl.registerReceiverInternal(ContextImpl.java:1329)
    at android.app.ContextImpl.registerReceiver(ContextImpl.java:1309)
    at android.app.ContextImpl.registerReceiver(ContextImpl.java:1303)
    at android.content.ContextWrapper.registerReceiver(ContextWrapper.java:554)
    at com.example.android.app.MainActivity.onCreate(MainActivity.java:264)
    at android.app.Activity.performCreate(Activity.java:6367)
    at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1110)
    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2404)
    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2511)
    at android.app.ActivityThread.access$900(ActivityThread.java:165)
    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1375)
    at android.os.Handler.dispatchMessage(Handler.java:102)
    at android.os.Looper.loop(Looper.java:150)
    at android.app.ActivityThread.main(ActivityThread.java:5621)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:794)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:684)

我在stackoverflow上读到一个类似的问题是取消注册BroadCastRecencer以修复此错误，但我有点迷失了如何做到这一点。

我已尝试将发送通知的意图更改为

Intent intent = new Intent("android.intent.action.MAIN");

但在这种情况下，当用户单击通知时，它不会执行任何操作。

有人知道如何修复它，以便用户单击时加载url吗？提前谢谢你

Answer 1

创建一个类似这样的方法

private PendingIntent retrievePlaybackAction(final String action) {
    Intent intent = new Intent(action);
    return PendingIntent.getBroadcast(this, 0, intent, PendingIntent.FLAG_UPDATE_CURRENT);
}

现在像这样添加您的意图

builder.setContentIntent(retrievePlaybackAction("OPEN_MAIN")); //change action text as you want

创建一个简单的类NotificationRecencer，我想你已经创建了，现在从您发送通知的地方创建此类的对象

private NotificationReceiver notificationReceiver;

在onCreate（）中注册您的接收器

notificationReceiver = new NotificationReceiver();

IntentFilter intentFilterNextClick = new IntentFilter("OPEN_MAIN");

registerReceiver(notificationReceiver, intentFilterNextClick); 
//can create exception, better to surround with try catch

在＜code＞onDestroy（）中

unregisterReceiver(notificationReceiver); 
//can create exception, better to surround with try catch

要打开或执行某些操作，请在接收器中添加此内容

@Override
public void onReceive(Context context, Intent intent) {
    Log.e(TAG, "onReceive: received " + intent.getAction());

    String action = intent.getAction();

    //no need to create switch you can also use if
    switch (action) {
        case "OPEN_MAIN":
            openMain();
            break;
    }

}

//here is openMain();
private void openMain(Context context) {
    Intent openMainIntent = new Intent(context, MainActivity.class);
    openMainIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK); //this flag is important
    context.startActivity(openMainIntent);
}

如果应用程序最小化或关闭，这也将起作用

希望这会有所帮助！

请询问您是否需要更多帮助！

Answer 2

从Android文档中可以看出:

如果它已声明其启动模式为“多”(默认)，并且您没有以相同的意图设置< code > FLAG _ ACTIVITY _ SINGLE _ TOP ，则它将被完成并重新创建。对于所有其他启动模式，或者如果设置了< code > FLAG _ ACTIVITY _ SINGLE _ TOP ，则此意图将被传递给当前实例的onNewIntent()。

因此，在创建新意图时设置FLAG_ACTIVITY_SINGLE_TOP标志应该解决并运行onNewIntent（）方法，而不是重新创建应用程序。