java:不兼容类型：推理变量U的边界不兼容

Question

错误：（65,52）java:不兼容类型：推理变量U的边界不兼容等式约束：akka。http。javadsl。模型HttpResponse下限：com。我的演员。聊天演员。聊天信息

下面这行代码显示了错误：

 CompletionStage<HttpResponse> httpResponse =
                        postChat(url,
                                context().system(), chatData)
                                .thenApplyAsync(httpResponse -> new ChatActor.ChatMessage(httpResponse,"1234"));


public static class ChatMessage{
   HttpResponse httpResponse;
    String name;

    public ChatMessage( HttpResponse httpResponse, String name) {
        this.httpResponse = httpResponse;
        this.name = name;
    }

    public HttpResponse getHttpResponse() {
        return httpResponse;
    }

    public String getname() {
        return name;
    }
}

这里是HttpResponse是Akka Http的。

我不知道它在说什么。解决它的方法应该是什么？

Answer 1

方法。然后应用同步（httpResponse-

所以只需更改变量的类型：

CompletionStage<ChatActor.ChatMessage> httpResponse =
     postChat(url, context().system(), chatData)
    .thenApplyAsync(httpResponse -> new ChatActor.ChatMessage(httpResponse,"1234"));

为什么编译器不简单地说“不能分配CompletionStage类型的实例？”