尝试向我的java web应用程序java.lang.IllegalStateException发出请求时出错：提交响应后无法调用senderRror（）

Question

  @GetMapping("/hello")
        public String hello_world()
        {
            return "Hello-World";
        }

-web.xml配置

 <servlet>
            <servlet-name>Faces Servlet</servlet-name>
            <servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/config/applicationContext.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

<context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/config/applicationContext.xml</param-value>
    </context-param>


    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>/faces/**</url-pattern>
    </servlet-mapping>

    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

    <servlet-mapping>
        <servlet-name>Faces Servlet</servlet-name>
        <url-pattern>*.xhtml</url-pattern>
    </servlet-mapping>

Answer 1

已解决：通过为DispatcherServlet添加映射

<servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/config/applicationContext.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

<servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>

然后请求url将如下所示

http://localhost:8080/rest/myendpoint