linux（Ubuntu）中systemd服务出错

Question

我写了下面的代码-

在filesystemwatcher.py中

import requests
import json
import logging
import sys
import os
import datetime
from watchdog.events import PatternMatchingEventHandler


class DirectoryChangedHandler(PatternMatchingEventHandler):

    patterns = ["*.json","*.csv"]

    logFileName = datetime.datetime.now().strftime('%Y%m%d_log.log')
    script_dir = os.path.dirname(__file__)  # <-- absolute dir the script is in
    rel_path = "log/"+logFileName
    abs_logfile_path = os.path.join(script_dir, rel_path)

    appConfigFilePath = os.path.abspath('config/app_config.json')
    with open(appConfigFilePath) as data_file:
        config = json.load(data_file)
    logging.basicConfig(filename=abs_logfile_path, format="%(asctime)s - %(name)s - %(levelname)s - %(message)s", level=logging.NOTSET)

    def process(self, event):

        print event.src_path, event.event_type
        try:

            filelist = [('files', open(event.src_path, 'rb'))]
            postUrl = self.config["apiBaseUrl"].encode('utf-8')+self.config["fileUplaodApiUrl"].encode('utf-8')
            uploadResponse = requests.post(postUrl, files=filelist)
            if uploadResponse.status_code == 200:
                print "Upload Successful - ", event.src_path
            else:
                print "Upload Failed - ", event.src_path
        except:
            print "Unexpected error:", sys.exc_info()[0]
            pass

    def on_modified(self, event):
        self.process(event)

    def on_created(self, event):
        self.process(event)

workflow.py-

#!/usr/bin/python2.7

import sys
import time
from watchdog.observers import Observer

import FileSystemWatcher as fSystemWatcher


if __name__ == '__main__':
    args = sys.argv[1:]
    observer = Observer()
    observer.schedule(fSystemWatcher.DirectoryChangedHandler(), path=args[0] if args else '.', recursive=True)
    observer.start()

    try:
        while True:
            time.sleep(1)
    except KeyboardInterrupt:
        observer.stop()

    observer.join()

和(/lib/systemd/system/filewatchersystemd.service)

[Unit]
Description=FileChangeService

[Service]
Type=forking
WorkingDirectory= /home/ashish/Documents/FileSystemWatcher
ExecStart= /home/ashish/Documents/FileSystemWatcher/workflow.py
Restart=on-failure

[Install]
WantedBy=multi-user.target

但我犯了一个错误-

FileWatcherSystemd.Service-FileChangeService loaded：loaded（/lib/systemd/system/FileWatcherSystemd.Service；enabled；vendor Preset：enabled）Active：inactive（dead）（结果：exit-code）自周三2017-07-19 10:44:39 IST以来；8min前进程:6552 execstart=/home/ashish/documents/filesystemwatcher/filesystemwatcher.py（代码=exited,status=203/exec)主PID:6552（代码=exited,status=203/exec)

7月19日10:44:39 Ashish-PC SystemD[1]:FileWatcherSystemd.Service：单元进入失败状态。7月19日10:44:39 Ashish-PC SystemD[1]:FileWatcherSystemd.Service：失败，结果为“exit-code”。Jull 19 10:44:39 Ashish-PC SystemD[1]:FileWatcherSystemd.Service：服务延迟时间结束，计划重新启动。7月19日10:44:39 Ashish-PC SystemD[1]:停止的FileChangeService。Jull 19 10:44:39 Ashish-PC SystemD[1]:FileWatcherSystemd.Service：启动请求重复得太快。7月19日10:44:39 Ashish-PC SystemD[1]:启动FileChangeService失败。

我不知道在FileSytemWatcher.py或FileWatcherSystemd.Service中做错了什么

Answer 1

尝试将您的服务类型更改为Simple。所以

type=simple

您的脚本似乎没有分叉和退出。如果您的服务类型是forking，systemd假定已启动的进程forks，在后台保留运行的内容并退出。它会一直等到脚本运行完毕。

您的脚本没有退出，systemd检测到这一点并给出超时错误。你的脚本好像在无限while循环中等待键盘中断。这种脚本可以作为“简单”运行。这意味着systemd只是在后台启动脚本，并继续执行启动序列，而无需等待任何事情。