Android Studio中的IllegalAccessException（目标Android为

Question

在我的android项目中，我最初的目标是Android6，它运行得很好。

现在我在一个Android4.4设备上运行它（包括一个真实设备和一个AVD)，它会因为一个IllegalAccessException而崩溃。

这就是它坠毁的地方

    this.PractitionerList.add(new
            PractitionerItem(1, "01A1234E", "Mary", "1st", "London", "Y")

    );

PractictionerItem是一个公共类，而PractictionerList是一个声明如下的arraylist

This.PractictionerList=new ArrayList（）；

这是logcat...

package org.nmc_uk.www.xxxxx;

import android.os.Parcel;
import android.os.Parcelable;

public class PractitionerItem implements Parcelable {
Integer PRN;
String PIN;
String Fname;
String Lname;
String Town;
String YesNo;



@Override
public int describeContents() {
    // TODO Auto-generated method stub
    return 0;
}

@Override
public void writeToParcel (Parcel dest, int flags) {
    dest.writeInt(PRN);
    dest.writeString(PIN);
    dest.writeString(Fname);
    dest.writeString(Lname);
    dest.writeString(Town);
    dest.writeString(YesNo);
}

private PractitionerItem(Parcel in){
    this.PRN = in.readInt();
    this.PIN = in.readString();
    this.Fname = in.readString();
    this.Lname = in.readString();
    this.Town = in.readString();
    this.YesNo = in.readString();
}

public static final Creator<PractitionerItem> CREATOR = new Creator<PractitionerItem>() {

    @Override
    public PractitionerItem createFromParcel(Parcel source) {
        return new PractitionerItem(source);
    }

    @Override
    public PractitionerItem[] newArray(int size) {
        return new PractitionerItem[size];
    }
};
public PractitionerItem(Integer PRN, String PIN, String Fname, String Lname, String Town, String YesNo){
    this.PRN = PRN;
    this.PIN = PIN;
    this.Fname = Fname;
    this.Lname = Lname;
    this.Town = Town;
    this.YesNo = YesNo;
}

Public class SearchTheRegister extends AppCompatActivity {

private ArrayList<PractitionerItem> PractitionerList;

private CustomAdapter practitioner_adapter;
.
.
.

 //// THIS LINE IS WHERE IT FAILS /////////////// 
    this.PractitionerList.add(new
            PractitionerItem(1, "01A1234E", "Mary", "1st", "London", "Y")

    );

有什么想法吗？

萨姆

Answer 1

我不确定这是否能解决您的问题，但我也有类似的问题，我意识到我的parcelable实现是错误的。我在下面为您生成了一个可打包的实现：

    @Override
    public int describeContents() {
        return 0;
    }

    @Override
    public void writeToParcel(Parcel dest, int flags) {
        dest.writeValue(this.PRN);
        dest.writeString(this.PIN);
        dest.writeString(this.Fname);
        dest.writeString(this.Lname);
        dest.writeString(this.Town);
        dest.writeString(this.YesNo);
    }

    public PractitionerItem() {
    }

    protected PractitionerItem(Parcel in) {
        this.PRN = (Integer) in.readValue(Integer.class.getClassLoader());
        this.PIN = in.readString();
        this.Fname = in.readString();
        this.Lname = in.readString();
        this.Town = in.readString();
        this.YesNo = in.readString();
    }

    public static final Creator<PractitionerItem> CREATOR = new Creator<PractitionerItem>() {
        @Override
        public PractitionerItem createFromParcel(Parcel source) {
            return new PractitionerItem(source);
        }

        @Override
        public PractitionerItem[] newArray(int size) {
            return new PractitionerItem[size];
        }
    };

如果这不起作用，您可以尝试在应用程序中添加multidex支持。关于KitKat、ArrayList和Parcelable有一个奇怪的问题。

要添加multidex支持,请执行以下操作：

首先改变你的等级，如下所示：

android {
    defaultConfig {
        ...
        multiDexEnabled true
        ...
    }
}

dependencies {
  ...
  compile 'com.android.support:multidex:1.0.0'
  ...

}

其次，从Multidex应用程序扩展应用程序，或在oncreate中调用Multidex.init:

public class YourApplication extends MultiDexApplication
{
    ...
}

public class YourApplication extends Application
{
    protected void attachBaseContext(Context base)
    {
        super.attachBaseContext(base);
        MultiDex.install(this);
    }
}