如何通过元素id从另一个数组中移除元素？[关闭]

Question

const arr1 = [{id:1,name:'qwerty'},{id:2,name:'qwerty'}]
const arr2 = [{id:1,name:'qwerty'},{id:2,name:'qwerty'},{id:3,name:'qwerty'},{id:4,name:'qwerty'}]

我需要按id从arr1中移除arr2中的所有元素

结果

const arr2 = [{id:3,name:'qwerty'},{id:4,name:'qwerty'}]

Answer 1

您可以从ARR1和筛选ARR2中获取具有所有ID的集。

这种方法

result = arr2.filter(
    (ids => ({ id }) => !ids.has(id))
    (arr1.reduce((s, { id }) => s.add(id), new Set))
);

在集的实例上使用带有IIFE（立即调用的函数表达式）的闭包

arr1.reduce((s, { id }) => s.add(id), new Set)

(ids => callback)(instanceOfSet)

({ id }) => !ids.has(id)

const
    arr1 = [{ id: 1, name: 'qwerty' }, { id: 2, name: 'qwerty' }],
    arr2 = [{ id: 1, name: 'qwerty' }, { id: 2, name: 'qwerty' }, { id: 3, name: 'qwerty' }, { id: 4, name: 'qwerty' }],
    result = arr2.filter(
        (ids => ({ id }) => !ids.has(id))
        (arr1.reduce((s, { id }) => s.add(id), new Set))
    );

console.log(result);

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