如何调用返回元组的函数[]

Question

相对来说，我是一个与Java智能合约交互的新手，在尝试检索智能合约函数返回的tuple[]时遇到了一个问题。这是我想调用的函数的ABI定义:

{
  "inputs":[{"internalType":"address","name":"account","type":"address"}],
  "name":"claimableRewards",
  "outputs":
    [{"components":
      [
        {"internalType":"address","name":"token","type":"address"},
        {"internalType":"uint256","name":"amount","type":"uint256"}
      ],
      "internalType":"struct MultiFeeDistribution.RewardData[]",
      "name":"rewards",
      "type":"tuple[]"
    }],
  "stateMutability":"view",
  "type":"function"
}

以下是智能合约代码的链接:https://polygonscan . com/address/0x 920 f 22 E1 e 5 da 04504 b 765 f 8110 ab 96 a 20 e 6408 BD # code

下面是我编写的调用该函数的Java代码(为了使代码更容易阅读，我删除了错误检查):

List<Type> claimableRewardsParams = Arrays.<Type>asList(new Address(credentials.getAddress()));
List<TypeReference<?>> claimableRewardsReturnTypes = Arrays.<TypeReference<?>>asList(new TypeReference<DynamicArray<DynamicStruct>>() {});

final Function claimableRewardsFunction = new Function(
        "claimableRewards",
        claimableRewardsParams,
        claimableRewardsReturnTypes);

String claimableRewardsEncodedFunction = FunctionEncoder
        .encode(claimableRewardsFunction);          

EthCall claimableRewardsResponse = web3.ethCall(
        Transaction.createEthCallTransaction(walletAddress, adamantRewardsContractAddress, claimableRewardsEncodedFunction),
        DefaultBlockParameterName.LATEST)
        .sendAsync().get();

List<Type> claimableRewardsSomeTypes = FunctionReturnDecoder.decode(
        claimableRewardsResponse.getValue(), claimableRewardsFunction.getOutputParameters());

当我运行程序时，我得到以下异常：

线程“main”java.lang.RuntimeException中的异常：TypeReferenced结构必须包含具有扩展类型的类型的构造函数

我已经尝试了其他几个可声明的奖励返回类型的定义，但我无法让它工作。有人能帮我吗？

Answer 1

    {
  "inputs":[{"internalType":"address","name":"account","type":"address"}],
  "name":"claimableRewards",
  "outputs":
    [{"components":
      [
        {"internalType":"address","name":"token","type":"address"},
        {"internalType":"uint256[]","name":"amount","type":"uint256[]"}
      ],
      "internalType":"struct MultiFeeDistribution.RewardData[]",
      "name":"rewards",
      "type":"tuple[]"
    }],
  "stateMutability":"view",
  "type":"function"
}

Answer 2

您需要定义一个扩展DynamicStruct的类

public class RewardData extends DynamicStruct {
    public RewardData(Address token, Uint256 amount) {
        super(new Type[]{token, amount});
    }
}

然后将DynamicSTRt替换为RewardData

List<TypeReference<?>> claimableRewardsReturnTypes = Arrays.<TypeReference<?>>asList(new TypeReference<DynamicArray<RewardData>>() {});