AWS Java SDK-无法通过区域提供程序链找到区域

Question

我已经完成了题为“以编程方式设置AWS区域1”的问题，但它并没有提供我所需要的全部答案。

Q1:我得到一个SDKClientException-无法通过region provider Chain找到一个region。我做错了什么？还是我漏掉了一个错别字。

public class CreateS3Bucket {

public static void main(String[] args) throws IOException {

    BasicAWSCredentials creds = new BasicAWSCredentials("aws-access-key", "aws-secret-key");
    AmazonS3 s3Client = AmazonS3ClientBuilder.standard().withCredentials(new AWSStaticCredentialsProvider(creds)).build();

    Region region = Region.getRegion(Regions.US_EAST_1);
    s3Client.setRegion(region);

    try {
        String bucketName = "testBucket" + UUID.randomUUID();
        s3Client.createBucket(bucketName);
        System.out.println("Bucket Created Successfully.");

    } catch(AmazonServiceException awse) {

        System.out.println("This means that your request made it AWS S3 but got rejected");
        System.out.println("Error Message:" +awse.getMessage());
        System.out.println("Error Message:" +awse.getErrorCode());
        System.out.println("Error Message:" +awse.getErrorType());
        System.out.println("Error Message:" +awse.getRequestId());

    } catch (AmazonClientException ace) {

        System.out.println("The Amazon Client encountered an Error with network Connectivity");
        System.out.println("Error Message:" + ace.getMessage());
    }


}

}

Q2:如果我想用它构建一个Lambda函数，需要做哪些代码更改？我知道如何创建lambda函数和它所需要的角色。只需要知道我编写的代码是否需要更改。我应该如何实现LambdaFuctionHandler类，如下所示：

import com.amazonaws.services.lambda.runtime.Context;
import com.amazonaws.services.lambda.runtime.RequestHandler;

 public class LambdaFunctionHandler implements RequestHandler<String, String> {

@Override
public String handleRequest(String input, Context context) {
    context.getLogger().log("Input: " + input);


    return null;
}

}

Answer 1

关于Q1，请尝试使用以下语法构建您的客户端：

AmazonS3 amazonS3 = AmazonS3Client.builder()
    .withRegion("us-east-1")
    .withCredentials(new AWSStaticCredentialsProvider(creds))
    .build();