在OnResponse或OnFailure中具有改型从不触发器的Post方法

Question

我正在尝试做一个带有改型的帖子，以检查服务器中是否存在一些数据。我的问题是nver经历了响应或失败。代码从不在这两个方法中传递。我在日志中没有发现任何错误。如果我进行调试，代码将停止在这里：call.enqueue（new Callback（））并在下一步转到方法之外。

如有帮助，将不胜感激

代码：

 ApiInterface apiService = ApiClient.getClient().create(ApiInterface.class);

        Call<User> call = apiService.smsPincodeCheck(getPhoneNuber, email);
        call.enqueue(new Callback<User>() {
            @Override
            public void onResponse(Call<User> call, Response<User> response) {
                if(response.isSuccess()){
                    Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
                }

                if(response.code() == 401){
                    Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
                }
            }

            @Override
            public void onFailure(Call<User> call, Throwable t) {

            }
        });

接口：

 @FormUrlEncoded
    @POST("api/check")
    Call<User> smsPincodeCheck(@Field("email") String email,  @Field("phoneNumber") String phoneNumber);

public class User implements Serializable {
    private final static String TAG = "User";

    @SerializedName("user")
    @Expose
    private Long id;
    private Long commerceId;
    private String email;
    private String name;
    private String lastname;
    private String dni;
    private String companyCharge;
.
.
. Getters and setters

{
  "phoneNumber" : "444444444", 
  "email" : "[e-mail]"
}

Call<ResponseSMS> call = apiService.smsPincodeCheck(getPhoneNuber, email);
    call.enqueue(new Callback<ResponseSMS>() {
        @Override
        public void onResponse(Call<ResponseSMS> call, Response<ResponseSMS> response) {
            if(response.isSuccess()){
                Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
            }

            if(response.code() == 401){
                Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
            }
        }

        @Override
        public void onFailure(Call<ResponseSMS> call, Throwable t) {
            Toast.makeText(RegisterThreeActivity.this, "Failure", Toast.LENGTH_SHORT).show();
        }
    });
}

接口：

Call<ResponseSMS> smsPincodeCheck(@Field("email") String email, @Field("phoneNumber") String phoneNumber);

型号：

public class ResponseSMS {
    public String response;
    public int status;

    public String getResponse() {
        return response;
    }

    public void setResponse(String response) {
        this.response = response;
    }

    public int getStatus() {
        return status;
    }

    public void setStatus(int status) {
        this.status = status;
    }
}

Answer 1

现在您需要创建一个单独的模型类来处理web服务的响应：

公共类响应{public String Response；public int status；}

并将该类替换为改型web服务调用中的user。

在：1中用响应替换用户。您的APIInterface接口的smspincodecheck方法。2.调用 调用=apiservice.smspincodecheck（getPhoneNuber,email）； 3。

call.enqueue(new Callback<Response>() {
            @Override
            public void onResponse(Call<Response> call, Response<Response> response) {
                if(response.isSuccess()){
                    Toast.makeText(RegisterThreeActivity.this, "200", Toast.LENGTH_SHORT).show();
                }

                if(response.code() == 401){
                    Toast.makeText(RegisterThreeActivity.this, "401", Toast.LENGTH_SHORT).show();
                }
            }

            @Override
            public void onFailure(Call<Response> call, Throwable t) {

            }
        });