改装始终响应onFailure

Question

我正在建立一个新的android项目并使用改版，我的改版功能在模拟器(NOX)和邮递员中正常工作，但是当我尝试在移动设备中构建我的应用程序时，改版总是陷入失败，有人能给我解决方案吗？我的API发布在公共主机上,

这就是我所说的改装

 private APIInterface getInterfaceService() {
        Retrofit retrofit = new Retrofit.Builder()
                .baseUrl(BASE_URL)
                .addConverterFactory(GsonConverterFactory.create())
                .build();
        final APIInterface mInterfaceService = retrofit.create(APIInterface.class);
        return mInterfaceService;
    }

 private void loginInterface(final String username, final String password){
        APIInterface mApiService = this.getInterfaceService();
        Call<Response> mService = mApiService.loginRequest(username,password);
        mService.enqueue(new Callback<Response>() {
            @Override
            public void onResponse(Call<Response> call, retrofit2.Response<Response> response) {
                if(response.body().getValue()==1){
                    Toast.makeText(Login.this,"Welcome",Toast.LENGTH_SHORT).show();
                    Intent intent = new Intent(getApplicationContext(),HomePage.class);
                    startActivity(intent);
                    finish();
                }else{
                    Toast.makeText(Login.this,"Invalid Username or Password",Toast.LENGTH_SHORT).show();
                }
            }

            @Override
            public void onFailure(Call<Response> call, Throwable t) {
                Toast.makeText(Login.this,t.getMessage(),Toast.LENGTH_SHORT).show();
            }
        });
    }

我的回应

 public class Response {

    @SerializedName("value")
    @Expose
    private Integer value;
    @SerializedName("result")
    @Expose
    private List<User> result = null;

    public Integer getValue() {
        return value;
    }

    public void setValue(Integer value) {
        this.value = value;
    }

    public List<User> getResult() {
        return result;
    }

    public void setResult(List<User> result) {
        this.result = result;
    }

}

 public class User {
    @SerializedName("id")
    @Expose
    private String id;
    @SerializedName("username")
    @Expose
    private String username;
    @SerializedName("password")
    @Expose
    private String password;
    @SerializedName("email")
    @Expose
    private String email;
    @SerializedName("image")
    @Expose
    private Object image;
    @SerializedName("point")
    @Expose
    private String point;
    @SerializedName("reputation")
    @Expose
    private String reputation;
    @SerializedName("role")
    @Expose
    private String role;

    public User(String id, String username, String password, String email, Object image, String point, String reputation, String role) {
        this.id = id;
        this.username = username;
        this.password = password;
        this.email = email;
        this.image = image;
        this.point = point;
        this.reputation = reputation;
        this.role = role;
    }

    public String getId() {
        return id;
    }

    public void setId(String id) {
        this.id = id;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public Object getImage() {
        return image;
    }

    public void setImage(Object image) {
        this.image = image;
    }

    public String getPoint() {
        return point;
    }

    public void setPoint(String point) {
        this.point = point;
    }

    public String getReputation() {
        return reputation;
    }

    public void setReputation(String reputation) {
        this.reputation = reputation;
    }

    public String getRole() {
        return role;
    }

    public void setRole(String role) {
        this.role = role;
    }
}

public interface APIInterface {
    @FormUrlEncoded
    @POST("login.php")
    Call<Response> loginRequest(@Field("username") String username,
                            @Field("password") String password);
}

android:usesCleartextTraffic="true"

{"value":1,"result":[{"id":"1","username":"username","password":"password","email":"email","image":null,"point":"0","reputation":"0","role":"2"}]}

这是我的邮差回复

Answer 1

当您试图在项目中使用翻新库时，您应该遵循的内容。

>

使用此网站将您的响应转换为POJO。需要示例，然后看看这个答案。

基本URL应以“/”结尾。

  String BASEURL = "http://www.xxxxxxxx.com/"

当您实现修改的回调时。您需要通过检查if(response.issucessful())来检查您的响应是否给出了200。

 mService.enqueue(new Callback<Response>() {
        @Override
        public void onResponse(Call<Response> call, retrofit2.Response<Response> response) {
        if(response.isSuccessful()){
           if(response.body().getValue()==1){
                Toast.makeText(Login.this,"Welcome",Toast.LENGTH_SHORT).show();
                Intent intent = new Intent(getApplicationContext(),HomePage.class);
                startActivity(intent);
                finish();
            }else{
                Toast.makeText(Login.this,"Invalid Username or Password",Toast.LENGTH_SHORT).show();
            }
          }else   Toast.makeText(Login.this,response.errorBody().string(),Toast.LENGTH_SHORT).show(); // this will tell you why your api doesnt work most of time
        }

        @Override
        public void onFailure(Call<Response> call, Throwable t) {
            Toast.makeText(Login.this,t.getMessage(),Toast.LENGTH_SHORT).show();
        }
    });

在你的邮递员，你包括9个头。你必须找出所有的9个头修改示例，并相应地将它们添加到你的API接口中。

注：-遵循这些事情，我想你会自己解决你的问题。

在更正以上所有说明后，请随时提出任何问题。