导出的可运行jar文件出现Java eclipse错误

Question

导出的jar文件有问题。当我在Eclipse中运行项目时，它运行得很好，但是当我从控制台作为导出的jar运行它时，我收到以下错误消息：

java.io.FileNotFoundException: firstLaunch.properties (System can't find file)
or
java.io.FileNotFoundException: resources/config/firstLaunch.properties (System can't find file)

代码如下：

public void saveConfigFile(String file, String key, String value) {
    Properties prop = new Properties();
    OutputStream output = null;

    try {

        output = new FileOutputStream(file);

        // set the properties value
        prop.setProperty(key, value);

        // save properties to project root folder
        prop.store(output, null);

    } catch (IOException io) {
        io.printStackTrace();
    } finally {
        if (output != null) {
            try {
                output.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }

    }
}

我执行该方法的语法是

if (properties.loadConfigFile("firstLaunch.properties", "value").equals(properties.loadConfigFile("true.properties", "true"))) {
        properties.saveConfigFile("port.properties", "port", "8795");
        properties.saveConfigFile("ip.properties", "ip", temp[1]);
        properties.saveConfigFile("firstLaunch.properties", "value", "false");
        settings.port = properties.loadConfigFile("port.properties", "port");
        settings.myIp = properties.loadConfigFile("ip.properties", "ip");
    } else {
        settings.port = properties.loadConfigFile("port.properties", "port");
        settings.myIp = properties.loadConfigFile("ip.properties", "ip");
    }

Answer 1

您的问题可能与您引用文件位置的方式有关。添加一些细节/代码示例，说明您是如何引用代码的，这样我们就可以确保提供帮助了。话虽如此，这里还有另一种引用属性文件的方法：

将其放在类路径中，如下所示：

private static Properties prop = new Properties();
private static String filename = "<name of file>.properties";
InputStream input = <ClassName>.class.getClassLoader().getResourceAsStream(filename);
try {

    if (input==null) {
        loggerOut.log(Level.SEVERE, "Sorry, unable to find " + filename);
    }
    prop.load(input);   
    loggerOut.info("XML In storage path: " prop.getProperty("<property in file>"));
    fileNameAndPath = prop.getProperty("fileNameAndPathIN").trim();
    logNameAndPath = logPath + logName;

} catch (IOException ex) {
    ex.printStackTrace();
} finally {
    if (input!=null) {
        try {
            input.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}