带有distinct的Panache查询返回PanacheQuery而不返回ArrayList

Question

List<String> list = repo
            .find("select DISTINCT(a.country) from TMdBrandAll a order by a.country")
            .page(Page.ofSize(1000)).list();

List<TMdBrandAll> list = brandAllRepo
            .find("select DISTINCT(a.country) from TMdBrandAll a order by a.country")
            .page(Page.ofSize(1000)).list();

我如何告诉Panache查询的结果将是ArrayList 而不是ArrayList ？

谢谢你的回答

编辑：回购代码：

@RequestScoped
@Transactional
public class BrandAllRepo implements PanacheRepositoryBase<TMdBrandAll, Long> {


    public void updateBrand(String brandName, String soundexCode, String countryCode, Long active, Long isNew, String user, Long brandAllId) {

        update("set brandName = ?1, soundexCode = soundex(pkg_util.f_escape_special_char1(?2))," +
                " countryCode = ?3, active = ?4, isNew = ?5, modifiedAt = sysdate, modified_by = ?6 where brandAllId = ?7",
            brandName, soundexCode, countryCode, active, isNew, user, brandAllId);

    }

}

@Inject
EntityManager em;

public List<String> findCountries() {
    List<String> qres = em
        .createQuery("select DISTINCT(a.countryCode) from TMdBrandAll a order by a.countryCode", String.class)
        .getResultList();

    return new ArrayList<>(qres);
}

Answer 1

这是对华丽的限制。

请查看代码https://github.com/quarkusio/quarkus/blob/master/extensions/panache/hibernate-orm-panache/runtime/src/main/java/io/quarkus/hibernate/orm/panache/panacheRepositorybase.java

它总是返回实体的列表。

在BrandAllRepo中创建返回字符串列表的finder方法,或者使用非类型化列表：

List list = brandAllRepo
        .find("select DISTINCT(a.country) from TMdBrandAll a order by a.country")
        .page(Page.ofSize(1000)).list();

你知道列表中会有字符串。

第二种选择就不那么好了。我会用第一种选择。