使用IN子句和subselect对多列进行Hibernate条件查询

Question

我有一个和这个问题很相似的问题。

我正在从表1中为表2中的字段3和字段4的所有匹配唯一组合选择所有数据。

select *
from table1 as t1
where (t1.field1, t1.field2) in (select distinct field3, field4
                                 from table2 as t2
                                 where t2.id=12345);

Criteria criteria = getSession().createCriteria(Table1.class);

DetachedCriteria subquery = DetachedCriteria.forClass(Table2.class);
ProjectionList projectionList = Projections.projectionList();
projectionList.add(Projections.property("field3"), "field3");
projectionList.add(Projections.property("field4"), "field4");
subquery.setProjection(Projections.distinct(projectionList));
subquery.add(Restrictions.eq("id", 12345));

我希望我的where子句类似于：

criteria.add(Subqueries.in("field1, field2", subquery));

但这是Hibernate不允许的。

我已经尝试推出where子句，使其具有两个子查询，并根据结果检查field1和field2，但似乎子查询总是必须返回多列。我使用group by完成了这个操作，但是Hibernate会自动将group by中的列添加到投影列表中，我无法找到删除它们的方法。

select *
from table1 as t1
where t1.field1 in (select field3
                    from table2 as t2
                    where t2.id=12345
                    group by field3, field4)
  and t1.field2 in (select field4
                    from table2 as t2
                    where t2.id=12345
                    group by field3, field4);

编辑：

@Larry.z使用HQL回答了我的问题。

我能够用Hibernate标准解决我的问题，但我必须将查询修改为：

select *
from table1 as t1
where exists (select 1
              table2 as t2
              where t2.id=12345
                and t2.field3=t1.field1
                and t2.field4=t1.field2);

Criteria criteria = getSession().createCriteria(Table1.class, "t1");

DetachedCriteria subquery = DetachedCriteria.forClass(Table2.class, "t2");
subquery.add(Restrictions.eq("t2.id", 12345));
subquery.add(Restrictions.eqProperty("t2.field3", "t1.field1"));
subquery.add(Restrictions.eqProperty("t2.field4", "t1.field2"));
subquery.setProjection(Projections.property("t2.id")); // select the ID rather than 1

我仍然好奇是否可以使用我的原始SQL编写Hibernate标准。

Answer 1

尝试这样编写HQL查询

String hql = "from Table1 t1 where (t1.field1, t1.field2) in (
    select distinct t2.field3, t2.field4
    from Table2 t2
    where t2.id=12345)";
sessionFactory.getCurrentSession().createQuery(hql).list()