spring integration 4.1.4。异常：无法找到XML架构的NamespaceHandler

Question

我用的是Spring2.2。我最近升级到了Spring4.1.4。

我的项目使用以下应用程序上下文：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:int="http://www.springframework.org/schema/integration"
       xmlns:int-file="http://www.springframework.org/schema/integration/file"
       xmlns:task="http://www.springframework.org/schema/task"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/task 
        http://www.springframework.org/schema/task/spring-task.xsd
        http://www.springframework.org/schema/context              
        http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/integration
        classpath:com/alu/motive/smdm/mediation/process/orchestration/activity/spring-integration.xsd">

Answer 1

不幸的是，您的命名空间配置未满。您声明int和int-filenls，但不声明它们的schemaLocation。如果您真的对Spring集成感兴趣，并且在类路径中有适当的JAR，请添加它们的schemaLocation:

http://www.springframework.org/schema/integration/file http://www.springframework.org/schema/integration/file/spring-integration-file.xsd
http://www.springframework.org/schema/integration http://www.springframework.org/schema/integration/spring-integration.xsd