包含以下[0-9]、[a-z]、[a-z]或特殊字符中至少3个的正则表达式（美元除外）

Question

我需要一个正则表达式来验证HTML中的输入字段。该模式应至少包含以下三项：

1. 数字[0-9]
2. 大写字母[A-Z]
3. 小写字母[a-z]
4. 特殊字符（美元除外）
5. 最小长度为6

有效输入字符串：

1. AAss11

无效的输入字符串：

1. AAAAA
2. AA11111
3. aa111111
4. AA@@@@@@
5. AAss11$
6. 1111111
<>@@@@@@
7. $1Asssss
8. AAss11@$

我写了这个正则表达式：

    ^(((?=.*[A-Z])(?=.*[a-z])(?=.*[0-9])[^$])|((?=.*[A-Z])(?=.*[a-z])(?=.
[!#%&'()*+,-./:;<=>?@[\]^_`{|}~])[^$])|((?=.*[A-Z])(?=.*[0-9])(?=.
[!#%&'()*+,-./:;<=>?@[\]^_`{|}~])[^$])|((?=.*[a-z])(?=.*[0-9])(?=.
[!#%&'()*+,-./:;<=>?@[\]^_`{|}~])[^$])).{6,16}$

Answer 1

你可以做所有的迭代（4次中的3次）。如果ECMAScript new出来了，并且
它支持条件（？（cond）yes|no）这被大大简化了。

在这里，它是无序的：

^(?:(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])|(?=.*[0-9])(?=.*[a-z])(?=.*[!"#%&'()*,\-./:;?@[\]_{}])|(?=.*[0-9])(?=.*[A-Z])(?=.*[!"#%&'()*,\-./:;?@[\]_{}])|(?=.*[a-z])(?=.*[A-Z])(?=.*[!"#%&'()*,\-./:;?@[\]_{}]))[0-9a-zA-Z!"#%&'()*,\-./:;?@[\]_{}]{6,16}$

扩展视图

 ^ 
 (?:
      (?= .* [0-9] )
      (?= .* [a-z] )
      (?= .* [A-Z] )
      #(?= .*[!"#%&'()*,\-./:;?@[\]_{}] )

   |  
      (?= .* [0-9] )
      (?= .* [a-z] )
      #(?= .*[A-Z] )
      (?= .* [!"#%&'()*,\-./:;?@[\]_{}] )

   |  
      (?= .* [0-9] )
      #(?= .*[a-z] )
      (?= .* [A-Z] )
      (?= .* [!"#%&'()*,\-./:;?@[\]_{}] )

   |  
      #(?= .*[0-9] )
      (?= .* [a-z] )
      (?= .* [A-Z] )
      (?= .* [!"#%&'()*,\-./:;?@[\]_{}] )

 )
 [0-9a-zA-Z!"#%&'()*,\-./:;?@[\]_{}]{6,16} 
 $ 

JS示例

var RxPwd = new RegExp("^(?:(?=.*[0-9])(?=.*[a-z])(?=.*[A-Z])|(?=.*[0-9])(?=.*[a-z])(?=.*[!\"#%&'()*,\\-./:;?@[\\]_{}])|(?=.*[0-9])(?=.*[A-Z])(?=.*[!\"#%&'()*,\\-./:;?@[\\]_{}])|(?=.*[a-z])(?=.*[A-Z])(?=.*[!\"#%&'()*,\\-./:;?@[\\]_{}]))[0-9a-zA-Z!\"#%&'()*,\\-./:;?@[\\]_{}]{6,16}$", "mg");

var strPwdTest = 
// Should pass
"AAss11\n"  +
"AA11@@\n"  +
"aa11@@\n"  +
"AAss@@\n"  +
// Should fail
"AAAAAA\n"  +
"AA11111\n"  +
"aa111111\n"  +
"AA@@@@@@\n"  +
"AAss11$\n"  +
"1111111\n"  +
"@@@@@@\n"  +
"$1Asssss\n"  +
"AAss11@$\n";

var match;

while ( match = RxPwd.exec( strPwdTest ) )
{
    console.log( match[0], "\t ..Passed" );
}