JSON解析抛出异常：

Question

我有一个包含OClass对象的列表。我想创建这个对象的JSON。下面是我的代码：

public void getClasss() {

    // returns all the top classes present in the ontology.

    classlist = new ArrayList<OClass>();     
    Set<OClass> topclasses = ontology.getOClasses(true);
    for (OClass oClasses : topclasses) {                
        classlist.add(oClasses);                
    }   

    OntoCreationClass ocreat = new OntoCreationClass();

    ocreat.OntoCreation(classlist);   
}

public class OntoCreationClass {    
    public static String data;
    public void OntoCreation(List<OClass> list) {

        System.out.println(list.get(0));

        OutputStream out = new ByteArrayOutputStream();

        ObjectMapper mapper = new ObjectMapper();

        try {
            mapper.writeValue(out, list);
        } catch (JsonGenerationException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (JsonMappingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

     }
}

com.fasterxml.jackson.databind.jsonMappingException：未发现用于com.ontotext.trree.owlim_ext.r类的序列化程序，也未发现用于创建BeanSerializer的属性（为了避免异常，禁用serializationconfig.serializationfeature.fail_on_empty_beans))（通过引用链:java.util.arraylist[0]->gate.creole.ontology.impl.oclassimpl[“ontology”]impl.sesame.sesameManager[“repositoryconnection”]-org.openrdf.repository.sail.sailrepositoryconnection[“repository”]-org

.openrdf.repository.sail.SailRepository["sail"]-com.ontotext.trree.owlim_ext.SailImpl["pool"])

>

我如何解决这个错误？有人能帮忙吗？

Answer 1

如果类中字段的访问修饰符为private，则必须放置Setter和Getter以使该类可序列化。

查看以下示例代码，以存储Person类的对象列表：

1-人员类：

public class Person {
    private String name;
    private int age;

    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    public void setAge(int age) {
        this.age = age;
    }
}

List<Person> persons = new ArrayList<Person>();
persons.add(new Person("Mike", 26));
persons.add(new Person("David", 20));
persons.add(new Person("Sara", 21));
persons.add(new Person("Amanda", 15));

3-那么现在就可以使用writeValue:

ObjectMapper objectMapper = new ObjectMapper();
    try {
        objectMapper.writeValue(new FileOutputStream(jsonPath), persons);
    } catch (IOException e) {
        e.printStackTrace();
    }

4-最后，您可以看到JSON文件：

[{"name":"Mike","age":26},{"name":"David","age":20},{"name":"Sara","age":21},{"name":"Amanda","age":15}]