JSP文件中的Lambda表达式将不会编译（续）

Question

我在这里发现了以下文章：JSP文件中的Lambda表达式将无法编译

因此，我在Tomcat的conf/web.xml中添加了compilerSourceVM和compilerTargetVM。（不在web.xml项目中）。

    <p>
    Cookies:<br />
    <%
        Cookie[] cookies = request.getCookies();
        if ( cookies == null || cookies.length == 0 ) {
            out.println("No cookies found<br/>");
        } else {
            out.println("Cookies found size=" + cookies.length + "<br/>");
            List<Cookie> cList = Arrays.stream(request.getCookies()).collect(Collectors.toList());
            for ( Cookie c : cList ) {
                out.println("C: " + c + "<br/>");
            }
            out.println("Cookies found size=" + cookies.length + "<br/>");
        }
    %>
</p>

  Arrays.stream(request.getCookies()).forEach(cookie -> {out.println("Cookie information here<br/>");});

    org.apache.jasper.JasperException: Unable to compile class for JSP: 
An error occurred at line: [53] in the jsp file: [/report.jsp]
Unhandled exception type IOException
50:             } else {
51:                 out.println("Cookies found size=" + cookies.length + "<br/>");
52:                 Arrays.stream(request.getCookies()).forEach(cookie -> {
53:                     out.println("Cookie information here<br/>");
54:                 });  

有什么提示吗？

提前谢了。

编辑：

Arrays.stream(request.getCookies()).forEach(cookie -> {System.out.println("Cookie information here<br/>");});

b.）out变量必须是final。因此需要final JspWriter myOut=out；

c.)您可能必须将JSP API库导入到我们的项目中。Gradle示例:providcompile'javax.servlet.JSP:javax.servlet.jsp-api:2.3.0'

Answer 1

是否可以尝试在web.xml中添加以下init参数，

    <init-param>
        <param-name>compilerSourceVM</param-name>
        <param-value>1.8</param-value>
    </init-param>
    <init-param>
        <param-name>compilerTargetVM</param-name>
        <param-value>1.8</param-value>
    </init-param>