后遗症ES6模型方法不存在

Question

'use strict';
const Sequelize = require("sequelize");

class Model extends Sequelize.Model {

  static init(sequelize, DataTypes) {
    return super.init(
      {
        // properties
      },
      { sequelize }
    );
  }

  static associate(models) {
  }


  async modelMethod() {

  }

}

module.exports = Model;

let modelClass = require('../models/' + modelFile);

let model = modelClass.init(sequelize, Sequelize);

然后在控制器文件中调用该模型作为控制器的属性

async controllerMethod(req, res) {
    let info = await this.model.modelMethod();
    res.send(info);
}

我收到的错误-

TypeError：this.model.modelMethod不是Controller.ControllerMethod(/usr/app/controllers/controller.js:83:41)位于Layer.Handle[as handle_request](/usr/app/node_modules/express/lib/router/Layer.js:95:5)位于next(/usr/app/node_modules/express/lib/router/Layer.js:137:13)位于:16:23)在promise._settlepromiseFromHandler(/usr/app/node_modules/bluebird/js/release/promise.js:512:31)在promise._settlepromise(/usr/app/node_modules/bluebird/js/release/promise.js:569:18)在promise._settlepromise0(/usr/app/node_modules/bluebird/js/release/promise.js:614:10)在

尝试输出类的方法会得到这样的结果-

console.log(Object.getOwnPropertyNames(this.model));


[ 'length',
  'prototype',
  'init',
  'associate',
  'name',
  'sequelize',
  'options',
  'associations',
  'underscored',
  'tableName',
  '_schema',
  '_schemaDelimiter',
  'rawAttributes',
  'primaryKeys',
  '_timestampAttributes',
  '_readOnlyAttributes',
  '_hasReadOnlyAttributes',
  '_isReadOnlyAttribute',
  '_dataTypeChanges',
  '_dataTypeSanitizers',
  '_booleanAttributes',
  '_dateAttributes',
  '_hstoreAttributes',
  '_rangeAttributes',
  '_jsonAttributes',
  '_geometryAttributes',
  '_virtualAttributes',
  '_defaultValues',
  'fieldRawAttributesMap',
  'fieldAttributeMap',
  'uniqueKeys',
  '_hasBooleanAttributes',
  '_isBooleanAttribute',
  '_hasDateAttributes',
  '_isDateAttribute',
  '_hasHstoreAttributes',
  '_isHstoreAttribute',
  '_hasRangeAttributes',
  '_isRangeAttribute',
  '_hasJsonAttributes',
  '_isJsonAttribute',
  '_hasVirtualAttributes',
  '_isVirtualAttribute',
  '_hasGeometryAttributes',
  '_isGeometryAttribute',
  '_hasDefaultValues',
  'attributes',
  'tableAttributes',
  'primaryKeyAttributes',
  'primaryKeyAttribute',
  'primaryKeyField',
  '_hasPrimaryKeys',
  '_isPrimaryKey',
  'autoIncrementAttribute',
  '_scope',
  '_scopeNames' ]

Answer 1

看了曼尼什的评论后，我决定重新尝试一下。

显然，for instance方法的工作方式是在调用.init方法后初始化模型。

所以-

let model = ModelClass.init(sequelize, Sequelize);
model = new model();