使用do-while反转数字

Question

import java.util.*;

public class Main {
    static int replace(int number){
        if (number == 0)
            return 0;
        int digit = number % 10;

        if (digit == 0)
            digit = 1;

        return (number/10) * 10 + digit;
    }

    static int Convert(int number){
        if (number == 0)
            return 0;
        else
        return replace(number);
    }

    public static void main(String[] args) {
        int number;
        Scanner kb = new Scanner(System.in);

        System.out.print("Enter the number : ");
        number = kb.nextInt();
        System.out.println("replace:"+replace(number));
        int a, m = 0, sum = 0;

        do{
            a = replace(number) % 10;
            m = m * 10 + a;
            sum = sum + a;
            number = replace(number) / 10;
        }
        while( replace(number) > 0);

        System.out.println("Reverse:"+m);
        System.out.println("Sum of digits:"+sum);
    }
}

反向：1132

数字总和：7

Answer 1

改为这样做

import java.util.*;

public class Main {
    static int replace(int number){
        if (number %10 == 0)
            return number += 1;
        return number;
    }

    static int Convert(int number){
        if (number == 0)
            return 0;
        else
            return replace(number);
    }

    public static void main(String[] args) {
        int number;
        Scanner kb = new Scanner(System.in);

        System.out.print("Enter the number : ");
        number = kb.nextInt();
        int a = 0, m = 0, sum = 0;

        number = replace(number);
        System.out.println("replace:" + number);

        do{
            a = number %  10;
            m = m * 10 + a;
            sum = sum + a;
            number /= 10;
        }
        while( number > 0);

        System.out.println("Reverse:"+m);
        System.out.println("Sum of digits:"+sum);
    }
}

您的代码从根本上是错误的，因为您替换数字的方式。

所做的更改：

1. 更改了替换算法（您不能将所有0值更改为1这是错误的，以及为什么您得到了错误的值）
2. 在进入循环之前替换数字。（您不需要在3个不同的地方替换循环的每次迭代）

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