Spring Data JPA-使用@Query与多对多关系/联接表

Question

    @Entity
@Table(name = "auth_user")
public class OAuthUser {

    // @Autowired
    // @Transient
    // private PasswordEncoder passwordEncoder;
    //
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    @Column(name = "username")
    private String userName;

    @Column(name = "password")
    @JsonIgnore
    private String password;

    @Column(name = "first_name")
    private String firstName;

    @Column(name = "last_name")
    private String lastName;

    @Column(name = "email")
    private String email;

    @Column(name = "is_enabled")
    private boolean isEnabled;

    /**
     * Reference:
     * https://github.com/nydiarra/springboot-jwt/blob/master/src/main/java/com/nouhoun/springboot/jwt/integration/domain/User.java
     * Roles are being eagerly loaded here because they are a fairly small
     * collection of items for this example.
     */
    @ManyToMany(fetch = FetchType.EAGER)
    @Fetch(value = FetchMode.SUBSELECT)
    @JoinTable(name = "user_role", joinColumns = @JoinColumn(name = "user_id", referencedColumnName = "id"), inverseJoinColumns = @JoinColumn(name = "role_id", referencedColumnName = "id"))
    private List<Role> roles;

    @ManyToMany(fetch = FetchType.EAGER)
    @Fetch(value = FetchMode.SUBSELECT)
    @JoinTable(name = "user_properties", joinColumns = @JoinColumn(name = "AuthID", referencedColumnName = "id"), inverseJoinColumns = @JoinColumn(name = "PropertyID", referencedColumnName = "id"))
    private List<Property> properties;

    @Query("SELECT u FROM auth_user as u WHERE u.isEnabled AND u.id IN"
        + " (SELECT r.user_id FROM user_role as r WHERE r.role_id = ?1)")
public List<OAuthUser> findByRole(int roleID);

谢了。

Answer 1

错误表示：

未映射auth_user

它引用查询中使用的auth_user，就像select u FROM auth_user一样。在查询中，它必须是oAuthUser。