Hibernate：psqlexception：错误：列“this_.user_id”不存在[已关闭]

Question

我知道这个问题已经在stackoverflow上被问过很多次了，我已经把所有的问题都问过了。但对我没什么用。所以我又发这个问题了。我在Postgres有一张桌子。DDL在下面。

CREATE TABLE  APPUSERMASTER (
 USER_ID BIGSERIAL NOT NULL,
 USER_NAME VARCHAR(20) NOT NULL,
 FIRST_NAME VARCHAR(20) NOT NULL,
 SECOND_NAME VARCHAR(20) NOT NULL,
 EMAIL VARCHAR(50) NOT NULL,
 PASSWORD TEXT  NOT NULL,
 PRIMARY KEY (USER_ID) 
) ;

我的POJO类在下面。

@Entity
@Table(name = "appusermaster", schema = "public")
public class UserMaster implements java.io.Serializable {

private long userId;
private String userName;
private String firstName;
private String secondName;
private String email;
private String password;

public UserMaster() {
}

@Id
@Column(name = "user_id", unique = true, nullable = false)
@GeneratedValue(strategy = GenerationType.IDENTITY)
public long getUserId() {
    return this.userId;
}

public void setUserId(long userId) {
    this.userId = userId;
}

@Column(name = "user_name", nullable = false, length = 20)
public String getUserName() {
    return this.userName;
}

public void setUserName(String userName) {
    this.userName = userName;
}

@Column(name = "first_name", nullable = false, length = 20)
public String getFirstName() {
    return this.firstName;
}

public void setFirstName(String firstName) {
    this.firstName = firstName;
}

@Column(name = "second_name", nullable = false, length = 20)
public String getSecondName() {
    return this.secondName;
}

public void setSecondName(String secondName) {
    this.secondName = secondName;
}

@Column(name = "email", length = 50)
public String getEmail() {
    return this.email;
}

public void setEmail(String email) {
    this.email = email;
}

@Column(name = "password", length = 20)
public String getPassword() {
    return this.password;
}

public void setPassword(String password) {
    this.password = password;
}

}

在我的DAO类中，我有以下代码。

public UserMaster getUserByUserName(String userName) {
    Criteria criteria = getSession().createCriteria(UserMaster.class); 
    criteria.add(Restrictions.eq("userName", userName));
    UserMaster userMaster = (UserMaster) criteria.uniqueResult();
    return userMaster;
}

但每当我执行这段代码时，我就会得到异常值以下的值。

[WARN ] 2017-07-18 18:24:23.105 [http-bio-8181-exec-9] SqlExceptionHelper - SQL Error: 0, SQLState: 42703
[ERROR] 2017-07-18 18:24:23.110 [http-bio-8181-exec-9] SqlExceptionHelper - ERROR: column this_.user_id does not exist
  Position: 8 org.hibernate.exception.SQLGrammarException: could not extract ResultSet
Caused by: org.postgresql.util.PSQLException: ERROR: column this_.user_id does not exist
  Position: 8
at org.postgresql.core.v3.QueryExecutorImpl.receiveErrorResponse(QueryExecutorImpl.java:2412)

我打开了hibernate的show sql属性，下面是sql正在生成。

Hibernate: 
select
    this_.user_id as user_id1_0_0_,
    this_.email as email4_0_0_,
    this_.first_name as first_na5_0_0_,
    this_.password as password6_0_0_,
    this_.second_name as second_n7_0_0_,
    this_.user_name as user_nam9_0_0_ 
from
    public.appusermaster this_ 
where
    this_.user_name=?
[WARN ] 2017-07-18 19:22:40.797 [http-bio-8181-exec-12] SqlExceptionHelper - SQL Error: 0, SQLState: 42703
[ERROR] 2017-07-18 19:22:40.814 [http-bio-8181-exec-12] SqlExceptionHelper -     ERROR: column this_.user_id does not exist
  Position: 8

Answer 1

日志显示的生成SQL正在从名为“usermaster”而不是“appusermaster”的表中选择记录

看起来它没有选择@table注释。如果您在java中更改了表的名称，可能是因为您的类文件已经过时，并且仍然引用旧的名称。