RegisterStoredProcedure.RegisterStoredProcedureParameter带出参数引用游标带Jpa Eclipse链接

Question

private static final String PERSISTENCE_UNIT_NAME = "todos";
private static EntityManagerFactory factory;

public static void main(String[] args) {

    factory = Persistence.createEntityManagerFactory(PERSISTENCE_UNIT_NAME);
    EntityManager em = factory.createEntityManager();

    em.getTransaction().begin();
    StoredProcedureQuery storedProcedure = em.createStoredProcedureQuery("TEST1");
    // set parameters
    storedProcedure.registerStoredProcedureParameter("P_CODE", String.class, ParameterMode.IN);
    storedProcedure.registerStoredProcedureParameter("P_DATE", String.class, ParameterMode.IN);
    storedProcedure.registerStoredProcedureParameter("P_CURSOR", ResultSet.class, ParameterMode.REF_CURSOR );
    storedProcedure.setParameter("P_CODE", "5110" );
    storedProcedure.setParameter("P_DATE", "01/01/2015" );
    // execute SP
    storedProcedure.execute();
    // get result
    Object obj =storedProcedure.getOutputParameterValue("tax");

    em.getTransaction().commit();
    em.close();

Answer 1

我认为您的存储存储过程返回列表，所以您在代码中做了一些更改。

旧代码

 storedProcedure.registerStoredProcedureParameter("P_CURSOR", ResultSet.class, ParameterMode.REF_CURSOR );

Object obj =storedProcedure.getOutputParameterValue("tax");

新代码

    storedProcedure.registerStoredProcedureParameter("P_CURSOR",void.class,ParameterMode.REF_CURSOR);

Object obj =storedProcedure.getResultList();