为什么我的程序不返回我在txt文件中搜索的文件行？

Question

嗨，这让我感到困惑，我正在尝试搜索我的文件中的选定数字，然后用该行的其余部分显示该数字，问题是我的程序似乎在我搜索它时返回第一行内容，但当我键入搜索它们时不会返回第二行或第三行

public static String searchProject(String searchTerm, String filepath) {
        String findString = "";
        boolean found = false;
        String projectNumber = "";
        String projectName = "";
        String typeProject = "";
        String address = "";
        String erf = "";
        String fee = "";
        String paid = "";
        String deadline = "";
        String finalised = "";
        String architectName = "";
        String architectTel = "";
        String architectEmail = "";
        String architectAddress = "";
        String contractorName = "";
        String contractorTel = "";
        String contractorEmail = "";
        String contractorAddress = "";
        String customerName = "";
        String customerTel = "";
        String customerEmail = "";
        String customerAddress = "";

        try {
            Scanner userInput = new Scanner(System.in);
            userInput = new Scanner(new File(filepath));
            userInput.useDelimiter("[,\n]");

            while (userInput.hasNext() && !found) {
                projectNumber = userInput.next();
                projectName = userInput.next();
                typeProject = userInput.next();
                address = userInput.next();
                erf = userInput.next();
                fee = userInput.next();
                paid = userInput.next();
                deadline = userInput.next();
                finalised = userInput.next();
                architectName = userInput.next();
                architectTel = userInput.next();
                architectEmail = userInput.next();
                architectAddress = userInput.next();
                contractorName = userInput.next();
                contractorTel = userInput.next();
                contractorEmail = userInput.next();
                contractorAddress = userInput.next();
                customerName = userInput.next();
                customerTel = userInput.next();
                customerEmail = userInput.next();
                customerAddress = userInput.next();

                if (projectNumber.equals(searchTerm)) {
                    findString = "\nProject Number: " + projectNumber + "\nProject Name: " + projectName + "\nType Project: " + typeProject + "\nAddress: "
                            + address + "\nERF number: " + erf + "\nTotal fee: R" + fee + "\nPaid to date: R" + paid + "\nProject Deadline: "
                            + deadline + "\nIs the project finalised: " + finalised + "\nArchitect Name: " + architectName + "\nArchitect Telephone: " + architectTel + "\nArchitect Email: "
                            + architectEmail + "\nArchitect Address: " + architectAddress + "\nContractor Name: " + contractorName + "\nContractor Telephone: " + contractorTel + "\nContractor Email: "
                            + contractorEmail + "\nContractor Address: " + contractorAddress + "\nCustomer Name: " + customerName + "\nCustomer Telephone: " + customerTel + "\nCustomer Email: "
                            + customerEmail + "\nCustomer Address: " + customerAddress;
                    System.out.println(findString);
                }
            }
        } catch (Exception e) {

        }
        return findString;
    }

我的 txt 文件内容

1,House mack,house,123 mack road,155,100000,40000,2022-09-14,no,Bill,123456,[e-mail],12 Bill road,Jack,456789,[e-mail],23 Jack road,John,789632,[e-mail],34 John road,
2,House John,house,123 John road,183,160000,50000,2022-09-10,yes,Bill,123456,[e-mail],12 Bill road,Jack,456789,[e-mail],23 Jack road,John,789632,[e-mail],34 John road,
3,House bill,house,123 bill road,193,160000,50000,2022-09-10,yes,Bill,123456,[e-mail],12 Bill road,Jack,456789,[e-mail],23 Jack road,John,789632,[e-mail],34 John road,

我正在寻找的输出

Please enter the project number to find the task: 1

Project Number: 1
Project Name: House mack
Type Project: house
Address: 123 mack road
ERF number: 155
Total fee: R100000
Paid to date: R40000
Project Deadline: 2022-09-14
Is the project finalised: no
Architect Name: Bill
Architect Telephone: 123456
Architect Email: [e-mail]
Architect Address: 12 Bill road
Contractor Name: Jack
Contractor Telephone: 456789
Contractor Email: [e-mail]
Contractor Address: 23 Jack road
Customer Name: John
Customer Telephone: 789632
Customer Email: [e-mail]
Customer Address: 34 John road

当我键入2或3以查找项目时，我的程序不显示任何问题，我该如何解决它？

Answer 1

问题是您的文本文件包含的列比解析代码预期的多一列（它在最后一个数据字段之后包含一个，这使得它总共有22列，您只读取其中的21列）。

由于这种不匹配，“第二”项目的读取从第一行的最后一个空字段开始，而不是从第二行的项目编号开始。

要检查这一点，您可以在阅读后立即写出< code>projectNumber:

            projectNumber = userInput.next();
            System.out.println("projectNumber=" + projectNumber);

解决这个问题的一种方法是在读取一行的所有字段后添加一个额外的userInput.nextLine（）；：

            customerAddress = userInput.next();
            userInput.nextLine();

但是依我看，更好的办法是重写代码，一行一行地读，把每一行单独分成几列。通过将整个文件作为一系列列来读取，您忽略了数据的结构，而这种结构可以帮助您发现数据和/或代码中的错误。

附加说明：为什么要创建一个new Scanner（System.in）；如果你从来没有使用过它？我说的是这两行：

    Scanner userInput = new Scanner(System.in);
    userInput = new Scanner(new File(filepath));

您应该将这两行替换为一行

    Scanner userInput = new Scanner(new File(filepath));