junit cucumber缺失步骤错误

Question

Java-Cucumber示例

看起来我缺少步骤，它是抱怨缺少步骤，并认为它们是未定义的

.功能文件：

Feature: Roman Feature

  Scenario: Convert Integer to Roman Number
  Given I am on the demo page
  When I pass number 1
  Then the roman result is I


  Scenario: Convert Integer to Roman Number
  Given I am on the demo page
  When I pass number 5
  Then the roman result is V

@When("^I pass number (\\d+)$")
    public void convert_numbers_to_roman(int arg1) throws Throwable {
       // convert number

    }



@Then("^the roman result is (\\d+)$")
    public void the_roman_result_is(int result) throws Throwable {
        // match result
    }

  Scenario: Convert Integer to Roman Number [90m# net/xeric/demos/roman.feature:3[0m
    [32mGiven [0m[32mI am on the demo page[0m             [90m# DemoSteps.i_am_on_the_demo_page()[0m
    [32mWhen [0m[32mI pass number [0m[32m[1m1[0m                    [90m# DemoSteps.convert_numbers_to_roman(int)[0m
    [33mThen [0m[33mthe roman result is I[0m

@Then("^the roman result is I$")
public void the_roman_result_is_I() throws Throwable {
    // Write code here that turns the phrase above into concrete actions
    throw new PendingException();
}

Answer 1

我会考虑将罗马数作为字符串捕获，因此使用正则表达式(.*)

然后步骤如下所示：

@Then("^the roman result is (.*)$")
public void the_roman_result_is_I(String expectedRoman) throws Throwable {
    // Write code here that turns the phrase above into concrete actions
    throw new PendingException();
}

这与塞巴斯蒂安的答案相似，但在我看来，是一个更简单的正则表达式。它捕获任何字符串并将其作为参数传递。