GraphQL服务器未启动的Spring Boot

Question

type Person {
    id: ID
    name: String!
    contact: Contact
}

type Query {
    countPersons: Long!
    findByName(name: String!): [Person]!
    findAllPerson: [Person]!
}

type Contact {
    id: ID
    emailId: String
    mobileNumber: String!
}

extend type Query {
    findAllContact: [Contact]!
    countContacts: Long!
    findByMobileNumber(mobileNumber: String!): [Contact]!
    findByEmailId(emailId: String!): [Contact]!
}

@Data
@NoArgsConstructor
@AllArgsConstructor
@Builder
@Entity
@Table(name = "persons")
public class Person extends BaseAbstractEntity {

    @Column(name="person_name", nullable = false)
    private String name;

    @OneToOne(fetch = javax.persistence.FetchType.LAZY)
    @JoinColumn(name = "contact_id", referencedColumnName = "id")
    private Contact contact;

}

@Data
@NoArgsConstructor
@AllArgsConstructor
@Builder
@Entity
@Table(name = "contacts")
public class Contact extends BaseAbstractEntity {

    @Column(name="contact_email_id")
    private String emailId;

    @Column(name="contact_mobile_number", nullable = false)
    private String mobileNumber;

    @OneToOne(mappedBy = "contact")
    private Person person;

}

public class Query implements GraphQLQueryResolver {

    private final PersonRepository personRepository;
    private final ContactRepository contactRepository;

    public Query(PersonRepository personRepository, ContactRepository contactRepository) {
        this.personRepository = personRepository;
        this.contactRepository = contactRepository;
    }

    public Iterable<Person> findAllPerson() {
        return personRepository.findAll();
    }
}

启动服务器时获取错误：

通用域名格式。柯萨托德夫。图ql。工具。SchemaClassScannerError:无法将类型定义（非NullType{type=ListType{type=TypeName{name='Person'}}}}）与java类型（类com.demo.graphql.entities.Person）匹配：java类不是列表或泛型类型信息丢失：类com。演示。图ql。实体。人

在查询中注释掉findByName和findAllPersonfindAllPerson后，应用程序启动：

type Query {
    countPersons: Long!
    # findByName(name: String!): [Person]!
    # findAllPerson: [Person]!
}

我认为问题在于查询响应中的[Person]，它是一个Person列表。

链接到应用程序：https://github.com/shubham-v/spring-boot-graphql-demo/

Answer 1

查看共享回购协议：

public Person findByName(String name) {
    return personRepository.findByName(name);
}

解析程序正在返回单个Person类对象，但架构需要Person列表。

尝试将架构更改为：

findByName(name: String!): Person!