如何在TypeScript/JavaScript[重复]中筛选数组中的唯一id

Question

我有一个对象数组，如何在TypeScript/JavaScript中筛选唯一id数组

列表数组-

[{
    global_id: "269a8bded9bd4ecaa0e501c170a71f5a"
    icon: "/odb/icons/ip/ip_32.svg"
    id: "269a8bded9bd4ecaa0e501c170a71f5a"
}, {
    global_id: "269a8bded9bd4ecaa0e501c170a71f5a"
    icon: "/odb/icons/ip/ip_32.svg"
    id: "269a8bded9bd4ecaa0e501c170a71f5a"
}, {
    global_id: 348
    icon: "/odb/icons/ip/ip_32.svg"
    id: 348
}, {
    global_id: 201
    icon: "/odb/icons/ip/ip_32.svg"
    id: 201
}]

Answer 1

下面是一个使用array.filter的解决方案

function uniqueArrayOfObject(array, keyToBeUnique) {
  // Filter by looking at the next objects if the key is present a second time
  return array.filter((x, xi) => !array.slice(xi + 1)
    .some(y => y[keyToBeUnique] === x[keyToBeUnique]));
}

function getRndInteger(min, max) {
  return Math.floor(Math.random() * (max - min)) + min;
}

const keys = [
  'a', 'b', 'c', 'd', 'e', 'f', 'g',
];

const generatedArray = [];

for (let i = 0; i < 100000; i += 1) {
  generatedArray.push({
    uniqueKey: keys[getRndInteger(0, keys.length - 1)],
    val: i,
  });
}

const start = Date.now();

const unique = uniqueArrayOfObject(generatedArray, 'uniqueKey');

console.log(unique);

console.log(`It took ${Date.now() - start}ms to unique`);