如何获取Exoplayer2.x的本地视频Uri

Question

MediaSource videoSource = new ExtractorMediaSource(mp4VideoUri,
    dataSourceFactory, extractorsFactory, null, null);

Uri mp4VideoUri = Uri.parse("android.resources://"+getPackageName()+"/"+R.raw.dog);

但是SimpleExaPlayerView保持黑色，我会得到以下错误：

com.google.android.exoplayer2.upstream.HttpDataSource$HttpDataSourceException: Unable to connect to android.resources://lt.wilkas.deleteexoplayer/2131099648

我做错了什么？

Answer 1

    PlayerView playerView = findViewById(R.id.player_view);

    SimpleExoPlayer player = ExoPlayerFactory.newSimpleInstance(this);

    // Bind the player to the view.
    playerView.setPlayer(player);

    // Produces DataSource instances through which media data is loaded.
    DataSource.Factory dataSourceFactory = new DefaultDataSourceFactory(this, Util.getUserAgent(this, "yourApplicationName"));

    // This is the MediaSource representing the media to be played.
    MediaSource firstSource = new ExtractorMediaSource.Factory(dataSourceFactory).createMediaSource(RawResourceDataSource.buildRawResourceUri(R.raw.dog));

    // Prepare the player with the source.
    player.prepare(firstSource);