验证Spring Jpa查询中参数的最小长度

Question

@Entity
@Table(name = "FOO")
public class Foo {

    @Id
    @GeneratedValue
    private Long id;

    @Column(name = "BAR", length = 16, nullable = false)
    private String bar;

    public String getBar() {
        return bar;
    }

    public void setBar(String bar) {
        this.bar = bar;
    }
}


public interface FooJpaRepository extends JpaRepository<Foo, Long> {

    @Transactional(propagation = Propagation.REQUIRED, readOnly = true)
    List<Foo> findByBar(String bar);
}

如果不创建JParePository的实现，这可能吗？

Answer 1

如果您正在使用Spring Boot，则可以使用验证：

https://docs.spring.io/spring-boot/docs/current/reference/htmlsingle/#boot-features-validation

首先用@validate注释repo，然后在方法参数上使用任何Bean验证注释。

@Validate
public interface FooJpaRepository extends JpaRepository<Foo, Long> {

    @Transactional(propagation = Propagation.REQUIRED, readOnly = true)
    List<Foo> findByBar(@Size(max = 16) String bar);
}