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问题:

方法公共摘要的查询验证失败

罗晨
2023-03-14

我正在使用Hibernate和Spring创建RESTAPI。我正在将培训师映射到mySQL中的表

Caused by: java.lang.IllegalArgumentException: Validation failed for query for method public abstract java.util.List io.fruitful.model.repos.TrainerRepository.getTrainerByFilter(java.lang.String,java.lang.Integer)!
at org.springframework.data.jpa.repository.query.SimpleJpaQuery.validateQuery(SimpleJpaQuery.java:93) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.jpa.repository.query.SimpleJpaQuery.<init>(SimpleJpaQuery.java:63) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.jpa.repository.query.JpaQueryFactory.fromMethodWithQueryString(JpaQueryFactory.java:76) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.jpa.repository.query.JpaQueryFactory.fromQueryAnnotation(JpaQueryFactory.java:56) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$DeclaredQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:139) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$CreateIfNotFoundQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:206) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.jpa.repository.query.JpaQueryLookupStrategy$AbstractQueryLookupStrategy.resolveQuery(JpaQueryLookupStrategy.java:79) ~[spring-data-jpa-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.lookupQuery(RepositoryFactorySupport.java:553) ~[spring-data-commons-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.lambda$mapMethodsToQuery$1(RepositoryFactorySupport.java:546) ~[spring-data-commons-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at java.util.stream.ReferencePipeline$3$1.accept(ReferencePipeline.java:193) ~[na:1.8.0_144]
at java.util.Iterator.forEachRemaining(Iterator.java:116) ~[na:1.8.0_144]
at java.util.Collections$UnmodifiableCollection$1.forEachRemaining(Collections.java:1049) ~[na:1.8.0_144]
at java.util.Spliterators$IteratorSpliterator.forEachRemaining(Spliterators.java:1801) ~[na:1.8.0_144]
at java.util.stream.AbstractPipeline.copyInto(AbstractPipeline.java:481) ~[na:1.8.0_144]
at java.util.stream.AbstractPipeline.wrapAndCopyInto(AbstractPipeline.java:471) ~[na:1.8.0_144]
at java.util.stream.ReduceOps$ReduceOp.evaluateSequential(ReduceOps.java:708) ~[na:1.8.0_144]
at java.util.stream.AbstractPipeline.evaluate(AbstractPipeline.java:234) ~[na:1.8.0_144]
at java.util.stream.ReferencePipeline.collect(ReferencePipeline.java:499) ~[na:1.8.0_144]
at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.mapMethodsToQuery(RepositoryFactorySupport.java:548) ~[spring-data-commons-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at org.springframework.data.repository.core.support.RepositoryFactorySupport$QueryExecutorMethodInterceptor.lambda$new$0(RepositoryFactorySupport.java:538) ~[spring-data-commons-2.0.8.RELEASE.jar:2.0.8.RELEASE]
at java.util.Optional.map(Optional.java:215) ~[na:1.8.0_144]

Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: trainers is not mapped [SELECT t from trainers t WHERE t.trainerName = :name AND t.accountId = :id]
at org.hibernate.hql.internal.ast.QuerySyntaxException.generateQueryException(QuerySyntaxException.java:79) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.QueryException.wrapWithQueryString(QueryException.java:103) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:217) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:141) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:115) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.engine.query.spi.HQLQueryPlan.<init>(HQLQueryPlan.java:77) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.engine.query.spi.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:153) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.internal.AbstractSharedSessionContract.getQueryPlan(AbstractSharedSessionContract.java:553) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
at org.hibernate.internal.AbstractSharedSessionContract.createQuery(AbstractSharedSessionContract.java:662) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
... 79 common frames omitted

实体:

  @Entity
@Table(name = "trainers")
public class Trainer implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "trainer_id", unique = true, nullable = false)
    private Integer trainerId;

    @Column (name = "trainer_name")
    private String trainerName;

    @Column (name = "account_id")
    private Integer accountId;

以下是回购代码:

     @Query(value = "SELECT t from trainers t WHERE t.trainerName = :name AND t.accountId = :id")
List<Trainer> getTrainerByFilter(@Param("name") String name,
                                 @Param("id") Integer id);

@Query(value=“SELECT*from trainers,其中account_id为null”,nativeQuery=true)List getTrainerNoAccount();

配置Sql:

    environment.setPackagesToScan("io.fruitful.model");

getTrainerNoAccount()工作正常。

共有2个答案

莘聪
2023-03-14
 @Query(value = "SELECT t from Trainer t WHERE t.trainerName = :name AND t.accountId = :id")
List<Trainer> getTrainerByFilter(@Param("name") String name,
                                 @Param("id") Integer id);

这样更改您的查询,因为JPA需要bean名而不是表名。

章昊
2023-03-14

Hibernate将您的实体映射为Trainer,即类的名称,因为您没有在@entity注释中指定名称param。因此,您的查询应该是“从培训师t中选择t…”。

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