用javascript将servlet传递的复杂对象存储到数组中

Question

var locations = new Array();
<c:forEach items="${photosName}" var="photo" varStatus="loop">
    locations["${loop.index}"] = "${photo}";
</c:forEach>

locations[i].latitude
locations[i].longitude
locations[i].accuracy

var locations = new Array();
<c:forEach items="${photosName}" var="photo" varStatus="loop">
    locations["${loop.index}"] = JSON.stringify("${photo}");
</c:forEach>
alert("latitude: "+locations[0].latitude+ " longitude: "+locations[0].longitude);

jsp中的Photo对象由此类表示：

@Entity
public class Loc implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE)
    private long id;
    private double latitude;
    private double longitude;
    private long time;
    private double accuracy;
    private int processed;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public double getLatitude() {
        return this.latitude;
    }

    public void setLatitude(double latitude) {
        this.latitude = latitude;
    }

    public double getLongitude() {
        return this.longitude;
    }

    public void setLongitude(double longitude) {
        this.longitude = longitude;
    }

    public long getTime() {
        return this.time;
    }

    public void setTime(long time) {
        this.time = time;
    }

    @Override
    public String toString() {
        return "latitude: " + latitude + " longitude: " + longitude + "time: "
                + time;
    }

    public double getAccuracy() {
        return accuracy;
    }

    public void setAccuracy(double accuracy) {
        this.accuracy = accuracy;
    }

    public int getProcessed() {
        return processed;
    }

    public void setProcessed(int processed) {
        this.processed = processed;
    }
}

Answer 1

尝试位置[“${loop.index}”]={json.stringify（“${photo}”）}；。然后您可以访问您所写的属性：

locations[i].latitude
locations[i].longitude
locations[i].accuracy

注意：photo是JSONObject的字符串表示。像这样：

JSONObject jsonPhoto = gson.toJson(photoObj) //photoObj is instance of your java photo object class
String photo = jsonPhoto.toString();

要将对象转换为json对象，可以使用GSON库。这里是一个很好的教程的链接。

<%@ page import="com.google.gson.Gson" %>   
<%GSON gson = new Gson();%>    
var photoArray = JSON.stringify(<%=gson.toJson(phtoObjects).toString()%>);